Aptitude Practice Question and Answer
8 Q: A sum of ₹ 3000 yields an interest of ₹ 1080 at 12% per annum simple interest in how many years ?
975 06116217a56340c20700ac41d
6116217a56340c20700ac41d- 14 Yearsfalse
- 23 Yearstrue
- 35 yearsfalse
- 42½ Yearsfalse
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Answer : 2. "3 Years"
Q: PQRS is square whose side is 20 cm. By joining opposite vertices of PQRS are get four triangles. What is the sum of the perimeters of the four triangles?
975 0600946dbda57152562aa88d5
600946dbda57152562aa88d5- 1false
- 2false
- 3false
- 4true
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Answer : 4. " "
Q: A rectangular grass plot 80 m × 60 m has two roads, each 10 m wide, running in the middle of it; one parallel to length and the other parallel to breadth. Find the cost of gravelling the roads at ₹ 2 per m2.
975 0600e8d83178b94051cdf9081
600e8d83178b94051cdf9081- 1₹ 2600true
- 2₹ 2680false
- 3₹ 2580false
- 4₹ 2500false
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Answer : 1. "₹ 2600 "
Q: A solid metallic cylinder of base radius 3 cm. and height 5 cm. is melted to form cones, each of height 1 cm. and base radius 1 mm. The number of cones is -
975 060b6e1d32f692872ec8c9f7b
60b6e1d32f692872ec8c9f7b- 112540false
- 213500true
- 324400false
- 411600false
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Answer : 2. "13500"
Q: 5-[4-{3-(3-3-6)}] is equal to:
975 05eeb6d2a3716d10a7a4a135c
5eeb6d2a3716d10a7a4a135c- 14false
- 20false
- 310true
- 46false
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Answer : 3. "10"
Q: A certain sum of Rs.4200 becomes Rs5523 at 11% p.a simple interest in a certain time. What is the simple interest on the sum of Rs. 4800 at the same rate and in same time period?
975 0602e408f6d461f66398818d3
602e408f6d461f66398818d3- 11346false
- 21512true
- 31506false
- 41495false
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Answer : 2. "1512 "
Q: If the angle of the elevation of sun is θ and the length of the shadow of a pole of length P is S, then
975 05efeb26e9bfe193cd14b7fde
5efeb26e9bfe193cd14b7fde- 1P=Scosθfalse
- 2P = S sinθfalse
- 3true
θ - 4P=S cotθfalse
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Answer : 3. "θ "
Q: If AD, BE and CF are medians of ∆ABC, then which one of the following statements is correct?
975 05efeb7539bfe193cd14ba741
5efeb7539bfe193cd14ba741- 1AD + BE + CF = AB + BC + CAfalse
- 2AD + BE + CF = √2 ( AB + BC + CA )false
- 3( AD + BE + CF ) < AB + BC + CAtrue
- 4AD + BE + CF > AB + BC + CAfalse
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