Aptitude Practice Question and Answer
8 Q: A sector area of 4% is removed from a circular sheet of paper of diameter 50 cm, If the remaining part is used to make a conical surface , then the ratio of radius and height of the-
777 060ba0308a906b340d16ac82d
60ba0308a906b340d16ac82d- 114 : 15false
- 225 : 18false
- 312 : 7false
- 424 : 7true
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Answer : 4. "24 : 7"
Q: A property fetches a net annual income of ₹1000 deducting all outgoings. The capitalized value of the property for the rate of interest 6% will be (in ₹) -
776 062ff7acffef7996822ddfa7c
62ff7acffef7996822ddfa7c- 1₹16667.00true
- 2₹15003.00false
- 3₹18000.00false
- 4None of the abovefalse
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Answer : 1. "₹16667.00"
Q: One filling pipe P is three times faster than another filling pipe Q, if P can fill tank in 24 hours, then what is the time taken to completely fill the tank if both the pipes are opened together?
775 062c3f5e931b6d20155fc54ee
62c3f5e931b6d20155fc54ee- 112 hoursfalse
- 218 hourstrue
- 316 hoursfalse
- 414 hoursfalse
- 5None of thesefalse
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Answer : 2. "18 hours"
Q: A cistern has 3 pipes A, B and C. A and B can fill it in 3 and 4 hours respectively, and C can empty it in 1 hour. If the pipes are opened at 3 p.m., 4 p.m. and 5 p.m. respectively on the same day, the cistern will be empty at-
775 0630359612876110d0951efd9
630359612876110d0951efd9- 17.12 p.m.true
- 27.15 p.m.false
- 37.10 p.m.false
- 47.18 p.m.false
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Answer : 1. "7.12 p.m."
Q: A shopkeeper marks an article 24% above its cost price and allows a 15% discount on the marked price. If he earns a profit of Rs. 27 by selling the article, then the selling price of the article is:
775 064f85038a910aab8f9ffdbf2
64f85038a910aab8f9ffdbf2- 1Rs. 522false
- 2Rs. 508false
- 3Rs. 527true
- 4Rs. 517false
- 5Rs. 817false
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Answer : 3. "Rs. 527"
Q: A alone can do a piece of work in 15 days, while B alone can do it in 20 days. They work together for 6 days and the rest of the work is done by C in 6 days. If they get Rs 800 for the whole work, how should they divide the money?
775 064f1e9943be218b6cde52171
64f1e9943be218b6cde52171- 1Rs. 320, Rs. 240 and Rs. 240true
- 2Rs. 640, Rs. 280 and Rs. 260false
- 3Rs. 320, Rs. 420 and Rs. 360false
- 4Rs. 360, Rs. 420 and Rs. 240false
- 5Rs. 320, Rs. 240 and Rs. 720false
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Answer : 1. "Rs. 320, Rs. 240 and Rs. 240"
Explanation :
Let's break down the problem step by step:
- A can complete the work in 15 days, so his daily work rate is 1/15 of the work per day.
- B can complete the work in 20 days, so his daily work rate is 1/20 of the work per day.
- A and B work together for 6 days. In these 6 days, their combined work rate is (1/15 + 1/20) = (4/60 + 3/60) = 7/60 of the work per day.
- In 6 days, they complete (6 * 7/60) = 42/60 of the work, which simplifies to 7/10 of the work.
Now, let C complete the remaining 3/10 of the work in 6 days. We can calculate C's daily work rate:
C's daily work rate = Work done by C in 6 days / 6 C's daily work rate = (3/10) / 6 C's daily work rate = 1/20 of the work per day.
Now, let's calculate the total amount earned by each worker:
A's share: A worked for 6 days at a rate of 1/15 of the work per day, so he completed (6 * 1/15) = 2/5 of the work. A's share of the money is (2/5) * Rs 800 = Rs 320.
B's share: B worked for 6 days at a rate of 1/20 of the work per day, so he completed (6 * 1/20) = 3/10 of the work. B's share of the money is (3/10) * Rs 800 = Rs 240.
C's share: C worked for 6 days at a rate of 1/20 of the work per day, so he completed (6 * 1/20) = 3/10 of the work. C's share of the money is (3/10) * Rs 800 = Rs 240.
Now, to check if the total amount is correct, you can add up their individual shares:
Rs 320 (A) + Rs 240 (B) + Rs 240 (C) = Rs 800
So, they should divide the money as follows:
- A gets Rs 320.
- B gets Rs 240.
- C gets Rs 240.
Q:Direction: Each of the questions consists of a question and two statements numbered I and II given below it. You have to decide whether the data provide in the statements are sufficient to answer the question. Read both the statements and Give answer.
(A) If the data in statement I alone are sufficient to answer the question, while the data in statement II alone not sufficient to answer the question;
(B) If the data in statement II alone are sufficient to answer the question, while the data in statement I all are not sufficient to answer the question;
(C) If the data either in statement I alone or in statement II alone are sufficient to answer the question;
(D) If the data even in both statements I and II together are not sufficient to answer the question;
(E) If the data in both statements I and II together are necessary to answer the question.
What is the two-digit number?
I. Sum of two digits of number is 12 and ratio between them is 2: 1.
II. Product of two digits of number is 32 and quotient of the two digits is 2.
775 05e9e6e95069c450d7c6e344c
5e9e6e95069c450d7c6e344c(A) If the data in statement I alone are sufficient to answer the question, while the data in statement II alone not sufficient to answer the question;
(B) If the data in statement II alone are sufficient to answer the question, while the data in statement I all are not sufficient to answer the question;
(C) If the data either in statement I alone or in statement II alone are sufficient to answer the question;
(D) If the data even in both statements I and II together are not sufficient to answer the question;
(E) If the data in both statements I and II together are necessary to answer the question.
I. Sum of two digits of number is 12 and ratio between them is 2: 1.
II. Product of two digits of number is 32 and quotient of the two digits is 2.
- 1Afalse
- 2Bfalse
- 3Cfalse
- 4Dtrue
- 5Efalse
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Answer : 4. "D"
Q: The sum of weights of A and B is 80 kg. 50% of A's weight is
774 064ccef6ba919c8488e304799
64ccef6ba919c8488e304799- 120 kgtrue
- 210 kgfalse
- 325 kgfalse
- 415 kgfalse
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Answer : 1. "20 kg"
Explanation :
Let's denote the weight of A as 𝑥x kg and the weight of B as 𝑦y kg.
Given:
- 𝑥+𝑦=80x+y=80 (Sum of weights of A and B is 80 kg)
- 0.5𝑥=56𝑦0.5x=65y (50% of A's weight is 5665 times the weight of B)
We can solve these two equations to find the values of 𝑥x and 𝑦y, and then calculate the difference between their weights.
From equation 2: 0.5𝑥=56𝑦0.5x=65y Multiply both sides by 2 to get rid of the fraction: 𝑥=56𝑦×2x=65y×2 𝑥=106𝑦x=610y 𝑥=53𝑦x=35y
Now substitute this expression for 𝑥x into equation 1: 53𝑦+𝑦=8035y+y=80 83𝑦=8038y=80 Multiply both sides by 3883: 𝑦=80×38y=80×83 𝑦=30y=30
Now that we have found the weight of B, we can find the weight of A using equation 1: 𝑥+30=80x+30=80 𝑥=80−30x=80−30 𝑥=50x=50
So, the weight of A is 50 kg and the weight of B is 30 kg.
Now, let's find the difference between their weights: Difference=Weight of A−Weight of BDifference=Weight of A−Weight of B Difference=50−30Difference=50−30 Difference=20Difference=20
Therefore, the difference between their weights is 20 kg.