If a + b + c = 6, a³ + b³+c³-3abc=342, then what is the value of ab + bc + ca?

If (3x – 2y) : (2x + 3y) = 5 : 6, then one of the values of $${\left({^3\sqrt { x}+\ ^3\sqrt { y}\over ^3\sqrt { x}-\ ^3\sqrt { y} } \right) \ }^2$$ is

If x² + x = 5 then the value of   $${(x+3)^3}+{1\over (x+3)^3}$$ is

If x = 332, y = 333, z = 335, then the value of x³ + y³ + z³ – 3xyz is

$$4a-{4\over a}+3=0$$ then the value of :   $$ a^3-{1\over a^3}+3=?$$

The expression   $${15(\sqrt { 10}+\sqrt { 5})\over \sqrt { 10}+\sqrt { 20}+\sqrt { 40}-\sqrt { 5}-\sqrt { 80}     }$$ is equal to:

If a + b – c = 0 then the value of 2b²c² + 2c²a² + 2a²b² –a⁴ – b⁴ – c⁴

If   $$ a={b^2\over b-a} $$  then the value of a³ + b³ is