Algebra Question with answer Practice Question and Answer
6 Q:Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.
(i) 2x² + 9x + 9 = 0
(ii) 15y² + 16y + 4 = 0
380 064d5cce8bd50dd8e2e15b3a3
64d5cce8bd50dd8e2e15b3a3(ii) 15y² + 16y + 4 = 0
- 1x > yfalse
- 2x < ytrue
- 3x ≥ yfalse
- 4x ≤ yfalse
- 5x = y or no relation can be established between x & y.false
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Answer : 2. "x < y "
Q:Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.
(i) 2x³ = $$ \sqrt {256}$$
(ii) 2y² – 9y + 10 = 0
381 064d5cd6ed02c5c746bdfa5ef
64d5cd6ed02c5c746bdfa5ef(ii) 2y² – 9y + 10 = 0
- 1x > yfalse
- 2x < yfalse
- 3x ≤ ytrue
- 4x ≥ yfalse
- 5x = y or no relation can be established between x & y.false
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Answer : 3. "x ≤ y"
Q:Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.
(i) 6x² – 11x + 4 = 0
(ii) 3y² – 5y + 2 = 0
371 064d5cdd980ef1e74b4d61cce
64d5cdd980ef1e74b4d61cce(ii) 3y² – 5y + 2 = 0
- 1x ≤ yfalse
- 2x < yfalse
- 3x ≥ yfalse
- 4x > yfalse
- 5x = y or no relation can be established between x & y.true
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- SingleChoice
Answer : 5. "x = y or no relation can be established between x & y."
Q:Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.
(i) 3x² + 11x + 10 = 0
(ii) 2y² + 11y + 14 = 0
417 064d5cec3bd50dd8e2e15c472
64d5cec3bd50dd8e2e15c472(ii) 2y² + 11y + 14 = 0
- 1x ≥ ytrue
- 2x ≤ yfalse
- 3x > yfalse
- 4x < yfalse
- 5x = y or no relation can be established between x & y.false
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Answer : 1. "x ≥ y"
Q:Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.
(i) 12x² + 11x + 2 = 0
(ii) 12y²+ 7y + 1 = 0
452 064d5cf55bd50dd8e2e15c604
64d5cf55bd50dd8e2e15c604(ii) 12y²+ 7y + 1 = 0
- 1x ≥ yfalse
- 2x > yfalse
- 3x < yfalse
- 4x ≤ yfalse
- 5x = y or no relation can be established between x & y.true
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Answer : 5. "x = y or no relation can be established between x & y."
Q:Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.
(i) 21x² + 10x + 1 = 0
(ii) 24y²+ 26y + 5 = 0
433 064d5cfffa79837744725ae33
64d5cfffa79837744725ae33(ii) 24y²+ 26y + 5 = 0
- 1x ≤ yfalse
- 2x ≥ yfalse
- 3x > yfalse
- 4x < yfalse
- 5x = y or no relation can be established between x & y.true
- Show AnswerHide Answer
- Workspace
- SingleChoice