Two equal circles of radius 4 cm intersect each other such that each passes through the center of the other. The length of the common chord is

ABC is an isosceles triangle with AB = AC, A circle through B touching AC at the middle point of Q, intersects AB at P. Then AP : AB is : 

The number of sides in two regular polygons are in the ratio of 5 : 4. The difference between their Interior angles of the polygon is 6⁰ . Then the number of sides are 

Two circles having radii 5 units intersect each other in such a way that each of them passes through the centre of the other. Then the length of their common chord is

An angle is four times its complementary angle. What is the measure of the angle?

ABCD is square and CDE is an equilateral triangle outside the square . What is the value ( in degrees ) of ∠BEC ? 

In a ∆ABC ∠A : ∠B : ∠C  = 2 : 3 : 4 . A line CD drawn || to AB, then the ∠ACD is: 

Two medians AD and BE of ∆ABC intersect G at right angle. If AD = 9 cm and BE = 6 cm, then the length of BD ( in cm ) is