Number System Questions Practice Question and Answer
8 Q: The product of 1.7 ´ 104 and 12.5 ´ 10–6 is expressed in the standard form as k ´ 10n . The value of (2k + n) is
458 064b79ec623047f4c71c89652
64b79ec623047f4c71c89652- 12.125false
- 21.125false
- 32.25false
- 43.25true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "3.25"
Q: The least number that should be added to 35460 so that the sum is exactly divisible by 3, 4, 5 and 7 is:
453 0647f2fb9e72c4684a1e258a6
647f2fb9e72c4684a1e258a6- 1180false
- 2420false
- 3240true
- 484false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "240 "
Q: What is the average of the first 13 odd numbers?
446 06433cedd72ca731a99272310
6433cedd72ca731a99272310- 114false
- 213.5false
- 312false
- 413true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "13"
Q: Two positive numbers differ by 1280. When the greater number is divided by the smaller number, the quotient is 7 and the remainder is 50. The greater number is:
445 064bfb2f4e2108a7239492d0d
64bfb2f4e2108a7239492d0d- 11558false
- 21458false
- 31585false
- 41485true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "1485"
Explanation :
Given :- Two positive numbers differ by 1280
When the greater number is divided by the smaller number The quotient is 7 and the remainder is 50
Concept :- Dividend = Quotient × divisor + remainder
Calculation :- Let greater number = a and Smaller number = b From question, ⇒ a - b = 1280 ....(1) Again from question, ⇒ a = 7b + 50 ....(2)
Put the value of a from equation (2) into equation (1) ⇒ 7b + 50 - b = 1280 ⇒ 6b = 1280 - 50 ⇒ 6b = 1230 ⇒ b = (1230/6) ⇒ b = 205
Put the value of b in equation (1) ⇒ a - 205 = 1280 ⇒ a = 1280 + 205 ⇒ a = 1485 ⇒ Greater number = 1485 ∴ Greater number is 1485
Q:Directions: Find the wrong number in the following number series:
2, 3, 8, 31, 154, 924, 6460
445 064d4b805ebd5c3747277ead0
64d4b805ebd5c3747277ead0- 1924true
- 26460false
- 3154false
- 48false
- 531false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "924"
Q: The product of the zeroes of the quadratic polynomial x2+7x+ 10 is
444 063108e9cd9ac741324b7c0e4
63108e9cd9ac741324b7c0e4- 112false
- 210true
- 332false
- 442false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "10"
Q: The sum of the squares of two natural consecutive odd numbers is 394. The sum of the numbers is –
442 06303357ffef7996822e8f226
6303357ffef7996822e8f226- 124false
- 232false
- 340false
- 428true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "28"
Explanation :
Let the consecutive odd numbers be x and (x+2)
We know that x2 + (x + 2)2 = 394
We know x2 + x2 + 4x + 4 = 394
We know 2 x2 +4x – 390 = 0
We know x2 + 2x – 195 = 0
We know (x +15) (x-13) = 0
We know x = 13
We know Required sum = 13 +15 =28
Q: Which of the following options has the greatest value?
439 06447715a883b29684408eaf9
6447715a883b29684408eaf9- 1(−99)+(−44)−12false
- 220+4+(−8)−2+3+6true
- 3(−18)−45+(−3−2)false
- 4(−22)+(−4−7)false
- Show AnswerHide Answer
- Workspace
- SingleChoice