The value of $${4- \sqrt{0.04} \over 4+\sqrt{0.4} } $$  is closed to

The value of 24 ÷ 4 ×(3 +3) ÷2 is:

Assume that
$$\sqrt{3} = 3.605 \ (approximately)  $$
$$\sqrt{130} = 11.40 \ (approximately)  $$
Find the value of
$$\sqrt{1.3} + \sqrt{1300}+\sqrt{0.013}  $$

The smallest natural number, by which 3000 must be divided to make the quotient a perfect cube, is : 

Simplify : $$\sqrt{[(12.1)^2-(8.1)^2]÷[(0.25)^2+(0.25)(19.95)]} $$

Find the value of given expression. 

[76 – {90 ÷ 5 ⨯ (24 – 36 ÷ 3) ÷ 3}] 

The value of $$ {\sqrt{0.6912}+{\sqrt{0.5292}}\over {\sqrt{0.6912}-{\sqrt{0.5292}}}}$$ is:

The value of x in the given equation
$$ {23 ^2 + \sqrt{x}=625}$$