If $$ {(x-2)^{2}+(y-{1\over2})^{2}}=0$$, then the value of $$ {x\over y}$$ is

Find the value of $$ (2 {1\over6}+1 {13\over18}-{1\over6}) × {16÷4}$$

If the average of 11, 23 and x is 40, then what is the value of x?

What is the value of $$ {0.55 × 4.5\over 0.81}$$ ?

When x = 1, then value of |2x – 1| + |x – 3| will be -

24% of 680 + 16 % of 525 – 22% of 450 =?

Simplify the following expression.

 25-(4÷2)+11.5+9.5

Direction: What approximate value will come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value)

(31.99)^1/5 × (80.78)^1/4 × (5.15)² = ? × 2.29