What is the value of $$ {\sqrt{625}+\sqrt{484}}$$

The sum of two positive numbers is 20% of the sum of their squares and 25% of the difference of their squares. If the numbers are x and y then, is equal to

If p = 101, then the value of   $$3\sqrt{p(p^2-3p+3)}$$ is

 $$6 {4\over 9}$$ % ..???kkk

The value of $$ \sqrt { 2^4} \ + \ ^{3}\sqrt {64} \  + \ ^4\sqrt { 2^8} \    $$ is :

If $$ {3^{a+3}×4^{a+6}×25^{a+1}\over{27}^{a-1}×8^{a-2}×125^{a+4}}={4\over15^{26}}$$ then the value of $$ {\sqrt{a+9}}$$.

Find value of $$ {^3\sqrt{\sqrt{0.000729}}}+^3{\sqrt{0.008}}$$

If p = 124, $$3\sqrt{p(p^2-3p+3)-1}=?$$