If $$x=(\sqrt2+1)^{1\over3} $$, the value of $$(x^3-{1\over {x^3}}) $$ is

$$ {x+{1\over{x}}}$$, then the value of $$ {x^2}+{1\over{x^2}}$$ is

Solve the following equation.

If a + b + c = 0, then a³+b³+c³ is equal to 

Simplification 

If then the value of

If average of two x and $$1\over x$$ (where x ≠ 0) is A, what will be the average of x³ and $$1\over {x^3}$$?

If $$ x={\sqrt3\over{2}}$$ then the value of $$ \sqrt{1+x}-\sqrt{1-x}$$ will be