Geometry Practice Question and Answer
8 Q: Given that (a²+b²)=60, then find the value of (a+b)²+(a–b)².
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606fdc870d3bb27a206a5f13- 190false
- 2120true
- 3140false
- 4150false
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Answer : 2. "120"
Q: The exterior angle of a regular polygon is one-third of its interior angle, the number of sides of the polygon is -
882 060376ebc9d90e74af72bde80
60376ebc9d90e74af72bde80- 16false
- 28true
- 33false
- 44false
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Answer : 2. "8"
Q: If AD, BE and CF are medians of ∆ABC, then which one of the following statements is correct?
879 05efeb7539bfe193cd14ba741
5efeb7539bfe193cd14ba741- 1AD + BE + CF = AB + BC + CAfalse
- 2AD + BE + CF = √2 ( AB + BC + CA )false
- 3( AD + BE + CF ) < AB + BC + CAtrue
- 4AD + BE + CF > AB + BC + CAfalse
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Answer : 3. "( AD + BE + CF ) < AB + BC + CA "
Q: A solid sphere of diameter 7 cm is cut into two equal halves. What will be the increase (in cm.2) in the total surface area?
877 160fe2ff8f8986716bdf6937a
60fe2ff8f8986716bdf6937a- 1$$88 cm.^2$$false
- 2$$77 cm.^2$$true
- 3$$56 cm.^2$$false
- 4$$66 cm.^2$$false
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Answer : 2. "$$77 cm.^2$$ "
Q: A field in the shape of a trapezium whose parallel sides are 200 meter and 400-meter-long, whereas each of other two sides is 260 meter long. What is the area (in m2) of the field?
877 05fc0df0996415e6951a995fe
5fc0df0996415e6951a995fe- 172,000true
- 252,000false
- 348,000false
- 460,000false
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Answer : 1. "72,000"
Q: If the numerical value of the perimeter of an equilateral triangle is √3 times the area of it, then the length of each side of the triangle is:
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609f9b50e9d81557e5b4c3a8- 12 Unitfalse
- 23 Unitfalse
- 34 Unittrue
- 46 Unitfalse
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Answer : 3. "4 Unit"
Q: PQRS is square whose side is 20 cm. By joining opposite vertices of PQRS are get four triangles. What is the sum of the perimeters of the four triangles?
872 0600946dbda57152562aa88d5
600946dbda57152562aa88d5- 1$$ {40{\sqrt{2}}}$$false
- 2$$ {40{\sqrt{2}}}+ 40 $$false
- 3$$ {40{\sqrt{2}}}+ 80 $$false
- 4$$ {80{\sqrt{2}}}+ 80 $$true
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Answer : 4. "$$ {80{\sqrt{2}}}+ 80 $$"
Q: The diagonals AC and BD of a cyclic quadrilateral ABCD intersect each other at the point P. Then, it is always true that
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5efea615d4461c5b47dcc2d5- 1AP . BP = CP . DPfalse
- 2AP . CD = AB . CPfalse
- 3BP . AB = CD . CPfalse
- 4AP . CP = BP . DPtrue
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