Percentage Practice Question and Answer
8 Q: If the total monthly income of 16 persons is ₹ 80,800 and the income of one of them is 120% of the average income, then his income is
617 063a98b87e590d4085fc68c79
63a98b87e590d4085fc68c79- 1₹ 5,050false
- 2₹ 6,060true
- 3₹ 6,160false
- 4₹ 6,600false
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Answer : 2. "₹ 6,060 "
Q: 35 percent of a number is 1249.5. What is 78 percent of that number?
613 0611e11ce3419655efd036031
611e11ce3419655efd036031- 12382.5false
- 22784.6true
- 32912.25false
- 42452.6false
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Answer : 2. "2784.6"
Q: The rate of wheat increased by 25%. How many percent may the use of wheat be reduced so that the expenditure on that item remains the same?
608 0609a663a4587a93a1dc85703
609a663a4587a93a1dc85703- 120%true
- 235%false
- 330%false
- 425%false
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Answer : 1. "20%"
Q: In a school, if there are 36% boys and 352 girls, then the number of boys is ________.
601 0638f359d9ebad6607ba2d606
638f359d9ebad6607ba2d606- 1204false
- 2198true
- 3244false
- 4156false
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Answer : 2. "198"
Q: If the population of a town is 12.000 and the population increases at the rate of 10% per annum, then find the population. after 3 years.
592 06426e27c72ca731a990e28e2
6426e27c72ca731a990e28e2- 115,972true
- 212,200false
- 311,200false
- 410,200false
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Answer : 1. "15,972"
Explanation :
To find the population after 3 years given that it increases at a rate of 10% per annum, you can use the formula for exponential growth:
𝑃=𝑃0×(1+𝑟)𝑛P=P0×(1+r)n
Where:
- 𝑃P = Population after 𝑛n years
- 𝑃0P0 = Initial population
- 𝑟r = Rate of increase (in decimal form)
- 𝑛n = Number of years
Given:
- 𝑃0=12,000P0=12,000 (Initial population)
- 𝑟=0.10r=0.10 (10% increase per annum)
- 𝑛=3n=3 (Number of years)
Substitute these values into the formula:
𝑃=12,000×(1+0.10)3P=12,000×(1+0.10)3
𝑃=12,000×(1.10)3P=12,000×(1.10)3
𝑃=12,000×(1.331)P=12,000×(1.331)
𝑃=15,972P=15,972
So, the population after 3 years would be approximately 15,972.
Q: The sum of weights of A and B is 80 kg. 50% of A's weight is $${5\over6}$$ times the weight of B. Find the difference between their weights.
591 064ccef6ba919c8488e304799
64ccef6ba919c8488e304799- 120 kgtrue
- 210 kgfalse
- 325 kgfalse
- 415 kgfalse
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Answer : 1. "20 kg"
Explanation :
Let's denote the weight of A as 𝑥x kg and the weight of B as 𝑦y kg.
Given:
- 𝑥+𝑦=80x+y=80 (Sum of weights of A and B is 80 kg)
- 0.5𝑥=56𝑦0.5x=65y (50% of A's weight is 5665 times the weight of B)
We can solve these two equations to find the values of 𝑥x and 𝑦y, and then calculate the difference between their weights.
From equation 2: 0.5𝑥=56𝑦0.5x=65y Multiply both sides by 2 to get rid of the fraction: 𝑥=56𝑦×2x=65y×2 𝑥=106𝑦x=610y 𝑥=53𝑦x=35y
Now substitute this expression for 𝑥x into equation 1: 53𝑦+𝑦=8035y+y=80 83𝑦=8038y=80 Multiply both sides by 3883: 𝑦=80×38y=80×83 𝑦=30y=30
Now that we have found the weight of B, we can find the weight of A using equation 1: 𝑥+30=80x+30=80 𝑥=80−30x=80−30 𝑥=50x=50
So, the weight of A is 50 kg and the weight of B is 30 kg.
Now, let's find the difference between their weights: Difference=Weight of A−Weight of BDifference=Weight of A−Weight of B Difference=50−30Difference=50−30 Difference=20Difference=20
Therefore, the difference between their weights is 20 kg.
Q: B is 10% more than A. C is 20% less than A. B is what percentage more than C?
584 064225a4b5bff3d098d0b98ea
64225a4b5bff3d098d0b98ea- 145%false
- 227.5%false
- 337.5%true
- 425%false
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Answer : 3. "37.5%"
Q: The number obtained by subtracting two-third of 75% of 600 from a number is 320, what is the original number?
578 0631090be7c72c07784688297
631090be7c72c07784688297- 1500false
- 2300false
- 3620true
- 4720false
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