Percentage Practice Question and Answer
8 Q: 35 percent of a number is 1249.5. What is 78 percent of that number?
635 0611e11ce3419655efd036031
611e11ce3419655efd036031- 12382.5false
- 22784.6true
- 32912.25false
- 42452.6false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "2784.6"
Q: If the total monthly income of 16 persons is ₹ 80,800 and the income of one of them is 120% of the average income, then his income is
632 063a98b87e590d4085fc68c79
63a98b87e590d4085fc68c79- 1₹ 5,050false
- 2₹ 6,060true
- 3₹ 6,160false
- 4₹ 6,600false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "₹ 6,060 "
Q: The rate of wheat increased by 25%. How many percent may the use of wheat be reduced so that the expenditure on that item remains the same?
624 0609a663a4587a93a1dc85703
609a663a4587a93a1dc85703- 120%true
- 235%false
- 330%false
- 425%false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "20%"
Q: In a school, if there are 36% boys and 352 girls, then the number of boys is ________.
620 0638f359d9ebad6607ba2d606
638f359d9ebad6607ba2d606- 1204false
- 2198true
- 3244false
- 4156false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "198"
Q: B is 10% more than A. C is 20% less than A. B is what percentage more than C?
617 064225a4b5bff3d098d0b98ea
64225a4b5bff3d098d0b98ea- 145%false
- 227.5%false
- 337.5%true
- 425%false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "37.5%"
Q: If the population of a town is 12.000 and the population increases at the rate of 10% per annum, then find the population. after 3 years.
609 06426e27c72ca731a990e28e2
6426e27c72ca731a990e28e2- 115,972true
- 212,200false
- 311,200false
- 410,200false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "15,972"
Explanation :
To find the population after 3 years given that it increases at a rate of 10% per annum, you can use the formula for exponential growth:
𝑃=𝑃0×(1+𝑟)𝑛P=P0×(1+r)n
Where:
- 𝑃P = Population after 𝑛n years
- 𝑃0P0 = Initial population
- 𝑟r = Rate of increase (in decimal form)
- 𝑛n = Number of years
Given:
- 𝑃0=12,000P0=12,000 (Initial population)
- 𝑟=0.10r=0.10 (10% increase per annum)
- 𝑛=3n=3 (Number of years)
Substitute these values into the formula:
𝑃=12,000×(1+0.10)3P=12,000×(1+0.10)3
𝑃=12,000×(1.10)3P=12,000×(1.10)3
𝑃=12,000×(1.331)P=12,000×(1.331)
𝑃=15,972P=15,972
So, the population after 3 years would be approximately 15,972.
Q: The sum of weights of A and B is 80 kg. 50% of A's weight is $${5\over6}$$ times the weight of B. Find the difference between their weights.
608 064ccef6ba919c8488e304799
64ccef6ba919c8488e304799- 120 kgtrue
- 210 kgfalse
- 325 kgfalse
- 415 kgfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "20 kg"
Explanation :
Let's denote the weight of A as 𝑥x kg and the weight of B as 𝑦y kg.
Given:
- 𝑥+𝑦=80x+y=80 (Sum of weights of A and B is 80 kg)
- 0.5𝑥=56𝑦0.5x=65y (50% of A's weight is 5665 times the weight of B)
We can solve these two equations to find the values of 𝑥x and 𝑦y, and then calculate the difference between their weights.
From equation 2: 0.5𝑥=56𝑦0.5x=65y Multiply both sides by 2 to get rid of the fraction: 𝑥=56𝑦×2x=65y×2 𝑥=106𝑦x=610y 𝑥=53𝑦x=35y
Now substitute this expression for 𝑥x into equation 1: 53𝑦+𝑦=8035y+y=80 83𝑦=8038y=80 Multiply both sides by 3883: 𝑦=80×38y=80×83 𝑦=30y=30
Now that we have found the weight of B, we can find the weight of A using equation 1: 𝑥+30=80x+30=80 𝑥=80−30x=80−30 𝑥=50x=50
So, the weight of A is 50 kg and the weight of B is 30 kg.
Now, let's find the difference between their weights: Difference=Weight of A−Weight of BDifference=Weight of A−Weight of B Difference=50−30Difference=50−30 Difference=20Difference=20
Therefore, the difference between their weights is 20 kg.
Q: The price of sugar increases by 15%. By what percentage should the consumption of sugar be decreased so that the expenditure on the purchase of sugar remains the same? [Give your answer correct to 2 decimal places.]
599 0643d140332185cce373eec85
643d140332185cce373eec85- 111.11%false
- 212.5%false
- 314.16%false
- 413.04%true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "13.04%"
Explanation :
To solve this problem, let's denote:
- Initial price of sugar = P
- Initial quantity consumed = Q
- Initial expenditure = PQ
After the price increases by 15%, the new price becomes 1.15P.
To keep the expenditure constant, the new quantity consumed (let's call it Q') can be calculated using the formula:
New expenditure = New price × New quantity
Setting the new expenditure equal to the initial expenditure:
PQ = (1.15P) * Q'
Now, solve for Q':
Q' = PQ / (1.15P)
Simplify:
Q' = Q / 1.15
Now, let's find the percentage decrease in consumption:
Percentage decrease = [(Q - Q') / Q] * 100
Substituting the value of Q':
Percentage decrease = [(Q - (Q / 1.15)) / Q] * 100
Percentage decrease = [(Q * (1 - 1/1.15)) / Q] * 100
Percentage decrease ≈ [(1 - 0.8696) * 100] ≈ 13.04%
Therefore, the consumption of sugar should be decreased by approximately 13.04% to keep the expenditure on the purchase of sugar the same after a 15% increase in price.