Percentage Practice Question and Answer

Q:

35 percent of a number is 1249.5. What is 78 percent of that number?

635 0

  • 1
    2382.5
    Correct
    Wrong
  • 2
    2784.6
    Correct
    Wrong
  • 3
    2912.25
    Correct
    Wrong
  • 4
    2452.6
    Correct
    Wrong
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Answer : 2. "2784.6"

Q:

If the total monthly income of 16 persons is ₹ 80,800 and the income of one of them is 120% of the average income, then his income is 

632 0

  • 1
    ₹ 5,050
    Correct
    Wrong
  • 2
    ₹ 6,060
    Correct
    Wrong
  • 3
    ₹ 6,160
    Correct
    Wrong
  • 4
    ₹ 6,600
    Correct
    Wrong
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Answer : 2. "₹ 6,060 "

Q:

The rate of wheat increased by 25%. How many percent may the use of wheat be reduced so that the expenditure on that item remains the same?

624 0

  • 1
    20%
    Correct
    Wrong
  • 2
    35%
    Correct
    Wrong
  • 3
    30%
    Correct
    Wrong
  • 4
    25%
    Correct
    Wrong
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Answer : 1. "20%"

Q:

In a school, if there are 36% boys and 352 girls, then the number of boys is ________.

620 0

  • 1
    204
    Correct
    Wrong
  • 2
    198
    Correct
    Wrong
  • 3
    244
    Correct
    Wrong
  • 4
    156
    Correct
    Wrong
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Answer : 2. "198"

Q:

B is 10% more than A. C is 20% less than A. B is what percentage more than C?

617 0

  • 1
    45%
    Correct
    Wrong
  • 2
    27.5%
    Correct
    Wrong
  • 3
    37.5%
    Correct
    Wrong
  • 4
    25%
    Correct
    Wrong
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Answer : 3. "37.5%"

Q:

If the population of a town is 12.000 and the population increases at the rate of 10% per annum, then find the population. after 3 years.

609 0

  • 1
    15,972
    Correct
    Wrong
  • 2
    12,200
    Correct
    Wrong
  • 3
    11,200
    Correct
    Wrong
  • 4
    10,200
    Correct
    Wrong
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Answer : 1. "15,972"
Explanation :

To find the population after 3 years given that it increases at a rate of 10% per annum, you can use the formula for exponential growth:

𝑃=𝑃0×(1+𝑟)𝑛P=P0×(1+r)n

Where:

  • 𝑃P = Population after 𝑛n years
  • 𝑃0P0 = Initial population
  • 𝑟r = Rate of increase (in decimal form)
  • 𝑛n = Number of years

Given:

  • 𝑃0=12,000P0=12,000 (Initial population)
  • 𝑟=0.10r=0.10 (10% increase per annum)
  • 𝑛=3n=3 (Number of years)

Substitute these values into the formula:

𝑃=12,000×(1+0.10)3P=12,000×(1+0.10)3

𝑃=12,000×(1.10)3P=12,000×(1.10)3

𝑃=12,000×(1.331)P=12,000×(1.331)

𝑃=15,972P=15,972

So, the population after 3 years would be approximately 15,972.


Q:

The sum of weights of A and B is 80 kg. 50% of A's weight is $${5\over6}$$ times the weight of B. Find the difference between their weights. 

608 0

  • 1
    20 kg
    Correct
    Wrong
  • 2
    10 kg
    Correct
    Wrong
  • 3
    25 kg
    Correct
    Wrong
  • 4
    15 kg
    Correct
    Wrong
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Answer : 1. "20 kg"
Explanation :

Let's denote the weight of A as 𝑥x kg and the weight of B as 𝑦y kg.

Given:

  1. 𝑥+𝑦=80x+y=80 (Sum of weights of A and B is 80 kg)
  2. 0.5𝑥=56𝑦0.5x=65y (50% of A's weight is 5665 times the weight of B)

We can solve these two equations to find the values of 𝑥x and 𝑦y, and then calculate the difference between their weights.

From equation 2: 0.5𝑥=56𝑦0.5x=65y Multiply both sides by 2 to get rid of the fraction: 𝑥=56𝑦×2x=65y×2 𝑥=106𝑦x=610y 𝑥=53𝑦x=35y

Now substitute this expression for 𝑥x into equation 1: 53𝑦+𝑦=8035y+y=80 83𝑦=8038y=80 Multiply both sides by 3883: 𝑦=80×38y=80×83 𝑦=30y=30

Now that we have found the weight of B, we can find the weight of A using equation 1: 𝑥+30=80x+30=80 𝑥=80−30x=80−30 𝑥=50x=50

So, the weight of A is 50 kg and the weight of B is 30 kg.

Now, let's find the difference between their weights: Difference=Weight of A−Weight of BDifference=Weight of A−Weight of B Difference=50−30Difference=50−30 Difference=20Difference=20

Therefore, the difference between their weights is 20 kg.

Q:

The price of sugar increases by 15%. By what percentage should the consumption of sugar be decreased so that the expenditure on the purchase of sugar remains the same? [Give your answer correct to 2 decimal places.]

599 0

  • 1
    11.11%
    Correct
    Wrong
  • 2
    12.5%
    Correct
    Wrong
  • 3
    14.16%
    Correct
    Wrong
  • 4
    13.04%
    Correct
    Wrong
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Answer : 4. "13.04%"
Explanation :

To solve this problem, let's denote:

  • Initial price of sugar = P
  • Initial quantity consumed = Q
  • Initial expenditure = PQ

After the price increases by 15%, the new price becomes 1.15P.

To keep the expenditure constant, the new quantity consumed (let's call it Q') can be calculated using the formula:

New expenditure = New price × New quantity

Setting the new expenditure equal to the initial expenditure:

PQ = (1.15P) * Q'

Now, solve for Q':

Q' = PQ / (1.15P)

Simplify:

Q' = Q / 1.15

Now, let's find the percentage decrease in consumption:

Percentage decrease = [(Q - Q') / Q] * 100

Substituting the value of Q':

Percentage decrease = [(Q - (Q / 1.15)) / Q] * 100

Percentage decrease = [(Q * (1 - 1/1.15)) / Q] * 100

Percentage decrease ≈ [(1 - 0.8696) * 100] ≈ 13.04%

Therefore, the consumption of sugar should be decreased by approximately 13.04% to keep the expenditure on the purchase of sugar the same after a 15% increase in price.

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