$$(1+tan θ+secθ)(1+cotθ-cosecθ)\over (sec θ+tan θ)(1-sin θ) $$ is equal to :

$$ secA(secA+tanA)(1-sinA)\over (cosec^2A-1)sin^2A$$ is equal to:

If $${cos^2θ\over cot^2θ-cos^2θ}=3,$$ where $${0^0<θ<90^0}$$ then the value of θ is:

If secθ + tanθ = 3, then the value of secθ is:

If $${secθ+tanθ\over secθ-tanθ}=2{51\over79}$$, then the value of sinθ is equal to:

$${sin^2θ\over cosθ(1+cosθ)}+{1+cosθ\over cosθ} =?$$

In △ABC, right angle at B, if   $$tan\ A={1\over 2}$$, then the value of $$sinA(cosC+cosA)\over cosC(sin C-sinA)$$ is :

The value of (tan²A+ cot²A-2)- sec²A cosec² A is: