Trigonometry Practice Question and Answer

Q:

If cos(2θ+54°) = sinθ, 0°<(2θ-54°)<90°, then what is the value of $$1\over tan5θ+cosec{5θ\over 2}$$   

467 0

  • 1
    $$3\sqrt { 2}$$
    Correct
    Wrong
  • 2
    $$2-\sqrt { 3}$$
    Correct
    Wrong
  • 3
    $$2\sqrt { 3}$$
    Correct
    Wrong
  • 4
    $$2+\sqrt { 3}$$
    Correct
    Wrong
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Answer : 2. "$$2-\sqrt { 3}$$ "

Q:

$$sinθ[(1-tanθ)tanθ+sec^2θ]\over (1-sinθ)tanθ(1+tanθ)(secθ+tanθ)$$ is equal to:

384 0

  • 1
    cosecθsecθ
    Correct
    Wrong
  • 2
    -1
    Correct
    Wrong
  • 3
    1
    Correct
    Wrong
  • 4
    sinθcosθ
    Correct
    Wrong
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Answer : 3. "1"

Q:

if $${secθ={a\over b},b≠0,then \ {{1-tan^2θ}\over 2-sin^2θ}  }=?$$

384 0

  • 1
    $${b^2(2b^2-a^2)}\over {a^2(a^2+b^2)}$$
    Correct
    Wrong
  • 2
    $${a^2(2b^2-a^2)}\over {b^2(a^2+b^2)}$$
    Correct
    Wrong
  • 3
    $${a^2(2b^2+a^2)}\over {b^2(a^2+b^2)}$$
    Correct
    Wrong
  • 4
    $${a^2(2b^2+a^2)}\over {b^2(a^2-b^2)}$$
    Correct
    Wrong
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Answer : 2. "$${a^2(2b^2-a^2)}\over {b^2(a^2+b^2)}$$"

Q:

$$\left({1\over cosecθ}-{1\over sinθ} \right)+{1\over {cosecθ-cotθ}} -{1\over secθ+tanθ} =?$$

449 0

  • 1
    sinθcosθ
    Correct
    Wrong
  • 2
    sinθtanθ
    Correct
    Wrong
  • 3
    secθcosecθ
    Correct
    Wrong
  • 4
    cosecθcotθ
    Correct
    Wrong
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Answer : 3. "secθcosecθ"

Q:

In ∆PQR, ∠Q=90°. If cot $$R={1\over 3}$$, then what is the value of $${secP(cosR+sinP)\over cosec \ R(sinR-cosecP)} $$?

402 0

  • 1
    $${2\over 7} $$
    Correct
    Wrong
  • 2
    $$-{2\over 3}$$
    Correct
    Wrong
  • 3
    $$-{2\over 7}$$
    Correct
    Wrong
  • 4
    $${2\over 7}$$
    Correct
    Wrong
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Answer : 3. " $$-{2\over 7}$$"

Q:

If sin 3A=cos(A+100), where 3A is an acute angel, then what is the value of $$2cosec{3A\over2}+6sin^23A-{3\over 2}tan^2\ 3A$$?

334 0

  • 1
    4
    Correct
    Wrong
  • 2
    $$7\over 4$$
    Correct
    Wrong
  • 3
    5
    Correct
    Wrong
  • 4
    $$17\over 2$$
    Correct
    Wrong
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Answer : 1. "4"

Q:

The value of   $${cosec^230^0sin^245^0+sec^260^0}\over {tan60^0cosec^245^0-sec^260^0tan45^0}$$ is 

365 0

  • 1
    $$-2\sqrt { 3}-2$$
    Correct
    Wrong
  • 2
    $$-3(2+\sqrt { 3})$$
    Correct
    Wrong
  • 3
    $$3(2+\sqrt { 3})$$
    Correct
    Wrong
  • 4
    $$2\sqrt { 3}-2$$
    Correct
    Wrong
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Answer : 2. " $$-3(2+\sqrt { 3})$$"

Q:

cosA(sec A – cosA)(cotA+tanA)=?

406 0

  • 1
    tan A
    Correct
    Wrong
  • 2
    cot A
    Correct
    Wrong
  • 3
    sec A
    Correct
    Wrong
  • 4
    sin A
    Correct
    Wrong
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Answer : 1. "tan A"

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