Trigonometry Practice Question and Answer

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Q:

Find the value of sin (1920°)

 629 0

  • 1
    1 / 2
    Correct
    Wrong
  • 2
    1 / √2
    Correct
    Wrong
  • 3
    √3 / 2
    Correct
    Wrong
  • 4
    1 / 3
    Correct
    Wrong
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Answer : 3. "√3 / 2 "

Q:

θθθθθ

 627 0

  • 1
    cosecθ
    Correct
    Wrong
  • 2
    secθ
    Correct
    Wrong
  • 3
    2cosθ
    Correct
    Wrong
  • 4
    2secθ
    Correct
    Wrong
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Answer : 4. "2secθ"

Q:

The elimination of θ from x cosθ-y sinθ=2 and x sinθ + ycosθ = 4 will give

 616 0

  • 1

    x2+y2=20

    Correct
    Wrong
  • 2

    3x2+y2=20

    Correct
    Wrong
  • 3

    x2-y2=20

    Correct
    Wrong
  • 4

    3x2-y2=10

    Correct
    Wrong
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Answer : 1. "

x2+y2=20

"

Q:

For any real value of θθ

 613 0

  • 1
    cotθ-cosecθ
    Correct
    Wrong
  • 2
    secθ-tanθ
    Correct
    Wrong
  • 3
    cosecθ-cotθ
    Correct
    Wrong
  • 4
    tanθ-secθ
    Correct
    Wrong
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Answer : 3. "cosecθ-cotθ"

Q:

if , then the value of is

 612 0

  • 1
    1
    Correct
    Wrong
  • 2
    0
    Correct
    Wrong
  • 3
    3
    Correct
    Wrong
  • 4
    2
    Correct
    Wrong
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Answer : 2. "0"

Q:

What is the value of the expression?

(tan0° tan1° tan2° tan3° tan4° …… tan89°)

 607 0

  • 1
    1
    Correct
    Wrong
  • 2
    1/2
    Correct
    Wrong
  • 3
    0
    Correct
    Wrong
  • 4
    2
    Correct
    Wrong
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Answer : 3. "0 "

Q:

The value of sin 730 + cos 1370 is:

 603 0

  • 1

    cos 130

    Correct
    Wrong
  • 2

    sin 130

    Correct
    Wrong
  • 3

    cos 180

    Correct
    Wrong
  • 4

    sin 180

    Correct
    Wrong
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Answer : 2. "

sin 130

"

Q:

(sinθ+cosecθ)2+(cos θ+ sec θ)2=?

 591 0

  • 1
    5 + tan2 θ + cot2 θ
    Correct
    Wrong
  • 2
    7 + tan2 θ - cot2 θ
    Correct
    Wrong
  • 3
    7 + tan2 θ + cot2 θ
    Correct
    Wrong
  • 4
    5 + tan2 θ - cot2 θ
    Correct
    Wrong
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Answer : 3. "7 + tan2 θ + cot2 θ"

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