Trigonometry Questions and Answers for Competitive Exams
If 2sinθ+ 15 cos2θ=7, 0°˂θ˂90°, then what is the value of $$ {3-tanθ\over 2+tanθ}$$?
(A) $$ {1\over 4}$$
(B) $$ {3\over 4}$$
(C) $$ {1\over 2}$$
(D) $$ {5\over 8}$$
Correct Answer : C
If Tan4x – Tan2x=1 then the value of Sin4x + Sin2x is__
(A) 1
(B) $$ {1\over 2}$$
(C) 3
(D) $$ {1\over 5}$$
Correct Answer : A
(sec A + tan A – 1) (sec A – tan A+1) =?
(A) cotA
(B) 2cotA
(C) tanA
(D) 2tanA
Correct Answer : D
The value of $$ {(cos {\ 9°}+sin{\ 81°}})({sec {\ {9°}+cosec{\ 81°}}})\over{sin{\ 56°}sec{\ 34° }}+ {cos{\ 25°}cosec{\ 65°}}$$ is:
(A) $$ {1\over 4}$$
(B) 4
(C) 2
(D) $$ {1\over 2}$$
Correct Answer : C
If sin2a = cos3a then the value of cot6 a – cot2a?
(A) 1
(B) 2
(C) 0
(D) -1
Correct Answer : A
Which of the following values suits for A to make the equation $$ {{ATan62°Sec 28°Cot 38°}\over {Cosec62°Tan11°}}=1$$ ?
(A) $$ {{Tan38°Tan79°}\over {Tan 28°}}$$
(B) $$ {{Tan28°Tan38°}\over {Tan 79°}}$$
(C) $$ {{Tan38°}\over {Tan 79°Tan28°}}$$
(D) $$ {{Tan28° Tan 79°}\over { Tan38°}}$$
Correct Answer : B
Solve the given equation.
$$ {{cot \ 30°}\over {1+sin\ 45°}}+{{1+sin\ 45°}\over cot \ 30°}=?$$
(A) $$ {5\sqrt{3}}-{6\sqrt{6}}\over 6$$
(B) $$ {3-2\sqrt{3}}$$
(C) $$ {14\sqrt{3}}-{5\sqrt{6}}\over 6$$
(D) $$ {6\sqrt{6}}-{5\sqrt{3}}\over 6$$
Correct Answer : C
If A and B are acute angles and Sec A =3; Cot B=4, then the value of $$ {Cosec^{2}A}+Sin^{2}B\over {Cot^{2}A+Sec^{2}B}$$ is:
(A) 2
(B) $$ {25\over 261}$$
(C) $$ {322\over 323}$$
(D) $$ {1\over 261}$$
Correct Answer : C
If $$ {sin\ θ\ cosec\ θ\over tan θ}=4 $$ then Find the value of tan θ ?
(A) 4
(B) $$ {1\over 4}$$
(C) 3
(D) 5
Correct Answer : B
Simplify $$ \sqrt{(1-sin^{2}θ) ÷(1-cos^{2}θ)}$$.
(A) Cot θ
(B) Tan θ
(C) Sec θ
(D) Cosec θ
Correct Answer : A
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Vikram Singh
Providing knowledgable questions of Reasoning and Aptitude for the competitive exams.
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