Trigonometry Questions and Answers for Competitive Exams

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Trigonometry Questions and Answers for Competitive Exams
Q :  

If a(tanθ+cotθ)=1, sinθ+cosθ=b and 0°<θ<90°, then the relation between a and b.

(A) $$ {2a={b^2}}+1$$

(B) $$ {b^2=2({a-1}})$$

(C) $$ {2a={b^2-1}}$$

(D) $$ {b^2=2({a+1}})$$


Correct Answer : C

Q :  

$$ {tan7°tan23°tan60°tan67°tan83°}$$ is equal to-

(A) 0

(B) $$ \sqrt{3}$$

(C) $$ 1\over \sqrt{3}$$

(D) None of these


Correct Answer : B

Q :  

What is the simplification value of $${cotA+tanB}\over{cotB+tanA}$$?

(A) tanAcotB

(B) tanBcotA

(C) tanAtanB

(D) cotAcotB


Correct Answer : B

Q :  

$$ {tan^2θ}$$ is equal to:-

(A) $$ {1\over cot^2{θ}}$$

(B) $$ {1\over sin^2{θ}}$$

(C) $$ {1\over cosec^2{θ}}$$

(D) $$ {1\over sec^2{θ}}$$


Correct Answer : A

Q :  

What is the value of $$ {cosecθ\sqrt{1-cos^2θ}}$$.

(A) 0

(B) – 2

(C) – Sinθ

(D) 1


Correct Answer : D

Q :  

If 4tanθ=3,the  value of $$ \left({4sinθ-2cosθ\over4sinθ+2cosθ}\right) $$ is:-

(A) $$ {2\over5}$$

(B) $$ {1\over5}$$

(C) $$ {4\over5}$$

(D) None of these


Correct Answer : B

Q :  

(secA – 1)/(secA + 1) is equal to?

(A) (1 – sinA)/(1 + sinA)

(B) (1 – cosA)/(1 + cosA)

(C) (1 + cosA)/(1 – cosA)

(D) (1 + sinA)/(1 – sinA)


Correct Answer : B

Q :  

Find the value tanθ-cosθ in the given figure.

(A) $${4\over5}$$

(B) $$-{4\over9}$$

(C) $$-{1\over20}$$

(D) $${3\over20}$$


Correct Answer : C

Q :  

If cos3A = X, then value of X?

(A) 4cos3A + 3cosA

(B) 3cosA – 4cos3A

(C) cosA + 4cos3A

(D) 4cos3A – 3cosA


Correct Answer : D

Q :  

If $$ {2sinθ-cosθ\over cosθ+sinθ}=1 $$ then the value of Cotθ is

(A) $$ {1\over4}$$

(B) $$ {1\over2}$$

(C) $$ {1\over3}$$

(D) $$ {2\over3}$$


Correct Answer : B

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    Vikram Singh

    Providing knowledgable questions of Reasoning and Aptitude for the competitive exams.

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