GATE Practice Question and Answer
8Q: One paper is equally folded 35 times, then what is the new thickness of the paper ? 2230 05b5cc74ae4d2b4197774fa8b
5b5cc74ae4d2b4197774fa8b- 1T(2^50)true
- 250Tfalse
- 32 x 50 Tfalse
- 4T/50false
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Answer : 1. "T(2^50)"
Explanation :
Answer: A) T(2^50) Explanation: Let initial thickness of the paper be 'T'after first fold it will be '2T' = 21Tafter second fold it will be '4T' = 22T after 50th fold it will be T x (250T)
Q: The absorption of ink by blotting paper involves 2225 05b5cc6a2e4d2b4197774cb7f
5b5cc6a2e4d2b4197774cb7f- 1viscosity of inkfalse
- 2diffusion of ink through the blottingfalse
- 3capillary action phenomenontrue
- 4siphon actionfalse
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Answer : 3. "capillary action phenomenon"
Explanation :
Answer: C) capillary action phenomenon Explanation: The absorption of ink by blotting paper involves capillary action phenomenon because the blotting paper is a thin and a smooth paper which allows a little thicker liquids like ink to absorb.
Q: A train for Fathehpur leaves for every 2 hrs 30 min from Agra station. An announcement was made that train left 37 mins ago and next train comes at 17:00hrs. At what time was the announcement made ? 2223 05b5cc715e4d2b4197774f445
5b5cc715e4d2b4197774f445- 115:07 hrstrue
- 215:20 hrsfalse
- 315:05 hrsfalse
- 415:00 hrsfalse
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Answer : 1. "15:07 hrs"
Explanation :
Answer: A) 15:07 hrs Explanation: Next train comes at 17:00 hrs.So, last train will be = 17:00hrs - 2:30hrs= 14:30hrsAnnouncement made after 37 min of the last train.S0, 14:30hrs + 00:37 min= 15:07 hrs.
Q: Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it? ___ utt ___ tt ___ ttu ___ 2220 05b5cc6f1e4d2b4197774ef59
5b5cc6f1e4d2b4197774ef59- 1t t u tfalse
- 2t u t tfalse
- 3t u u ttrue
- 4t t t ufalse
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Answer : 3. "t u u t"
Explanation :
Answer: C) t u u t Explanation: t, u, u and t. The sequence is : tut tut tut tut.
Q: Which of the following is not an aerosol? 2220 05b5cc699e4d2b4197774c691
5b5cc699e4d2b4197774c691- 1mudtrue
- 2dustfalse
- 3smokefalse
- 4fogfalse
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Answer : 1. "mud"
Explanation :
Answer: A) mud Explanation: Among the given options, mud is not an aerosol. An aerosol is a suspension of fine solid particles or liquid droplets, in the air or another gas. Aerosols can be natural or anthropogenic. Examples of natural aerosols are fog, dust, forest exudates and geyser steam. Examples of anthropogenic aerosols are haze, particulate air pollutants, and smoke.
Q: In a hostel, there was food for 1000 students for one month. After 10 days, 1000 more students joined the hostel. How long would the students be able to carry on with the remaining food? 2219 05b5cc774e4d2b41977750025
5b5cc774e4d2b41977750025- 110 daystrue
- 215 daysfalse
- 320 daysfalse
- 45 daysfalse
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Answer : 1. "10 days"
Explanation :
Answer: A) 10 days Explanation: After 10 days, the remaining food would be sufficient for the 1000 students for 20 more days -->If 1000 more students are added, it shall be sufficient for only 10 days (as the no. of students is doubled, the days are halved).
Q: On 24th Nov, 2007 Thursday falls. What day of the week was it on 10th Nov, 2006 ? 2217 05b5cc75ce4d2b4197774fc20
5b5cc75ce4d2b4197774fc20- 1Wednesdaytrue
- 2Tuesdayfalse
- 3Fridayfalse
- 4Thursdayfalse
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Answer : 1. "Wednesday"
Explanation :
Answer: A) Wednesday Explanation: The year 2006 is an ordinary year. So, it has 1 odd day.So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.But, 24th Nov, 2007 is Thursday. 24 - 10 = 14 days. Therefore, 2 weeks ago it is same day. Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.
Q: Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each gentleman received twice the paise as each lady received. Find the number of gentlemen in the family? 2211 05b5cc67be4d2b4197774c1f0
5b5cc67be4d2b4197774c1f0- 123true
- 292false
- 348false
- 452false
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Answer : 1. "23"
Explanation :
Answer: A) 23 Explanation: Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115 ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23 Hence, required number of gentlemen in the family = x = 23.