Quantitative Aptitude Practice Question and Answer

Q: If A1, A2, A3, A4, ..... A10 are speakers for a meeting and A1 always speaks after, A2 then the number of ways they can speak in the meeting is 1430 0

  • 1
    9!
    Correct
    Wrong
  • 2
    9!/2
    Correct
    Wrong
  • 3
    10!
    Correct
    Wrong
  • 4
    10!/2
    Correct
    Wrong
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Answer : 4. "10!/2"
Explanation :

Answer: D) 10!/2 Explanation: As A1 speaks always after A2, they can speak only in  1st  to 9th places and    A2 can speak in 2nd to 10 the places only when A1 speaks in 1st place    A2 can speak in 9 places the remaining     A3, A4, A5,...A10  has no restriction. So, they can speak in 9.8! ways. i.e   when A2 speaks in the first place, the number of ways they can speak is 9.8!.   When A2 speaks in second place, the number of ways they can speak is  8.8!.   When A2 speaks in third place, the number of ways they can speak is  7.8!. When A2 speaks in the ninth place, the number of ways they can speak is 1.8!       Therefore,Total Number of ways they can  speak = (9+8+7+6+5+4+3+2+1) 8! = 92(9+1)8! = 10!/2

Q: The number of ways that 7 teachers and 6 students can sit around a table so that no two students are together is 1196 0

  • 1
    7! x 7!
    Correct
    Wrong
  • 2
    7! x 6!
    Correct
    Wrong
  • 3
    6! x 6!
    Correct
    Wrong
  • 4
    7! x 5!
    Correct
    Wrong
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Answer : 2. "7! x 6!"
Explanation :

Answer: B) 7! x 6! Explanation: The students should sit in between two teachers. There are 7 gaps in between teachers when they sit in a roundtable. This can be done in 7P6ways. 7 teachers can sit in (7-1)! ways.    Required no.of ways is = 7P6.6! = 7!.6!

Q: The number of ways that 8 beads of different colours be strung as a necklace is 2071 0

  • 1
    2520
    Correct
    Wrong
  • 2
    2880
    Correct
    Wrong
  • 3
    4320
    Correct
    Wrong
  • 4
    5040
    Correct
    Wrong
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Answer : 1. "2520"
Explanation :

Answer: A) 2520 Explanation: The number of ways of arranging n beads in a necklace is (n-1)!2=(8-1)!2=7!2 = 2520  (since n = 8)

Q: In How many ways can the letters of the word 'CAPITAL' be arranged in such a way that all the vowels always come together? 919 0

  • 1
    360
    Correct
    Wrong
  • 2
    720
    Correct
    Wrong
  • 3
    120
    Correct
    Wrong
  • 4
    840
    Correct
    Wrong
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Answer : 1. "360"
Explanation :

Answer: A) 360 Explanation: CAPITAL = 7   Vowels = 3 (A, I, A)   Consonants = (C, P, T, L)   5 letters which can be arranged in  5P5=5!   Vowels A,I = 3!2!   No.of arrangements = 5! x 3!2!=360

Q: In how many ways the letters of the word 'DESIGN' can be arranged so that no consonant appears at either of the two ends? 1009 0

  • 1
    240
    Correct
    Wrong
  • 2
    72
    Correct
    Wrong
  • 3
    48
    Correct
    Wrong
  • 4
    36
    Correct
    Wrong
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Answer : 3. "48"
Explanation :

Answer: C) 48 Explanation: DESIGN = 6 letters   No consonants appear at either of the two ends.  = 2 x 4P4 =  2 x 4 x 3 x 2 x 1=  48

Q: Using numbers from 0 to 9 the number of 5 digit telephone numbers that can be formed is 1090 0

  • 1
    1,00,000
    Correct
    Wrong
  • 2
    59,049
    Correct
    Wrong
  • 3
    3439
    Correct
    Wrong
  • 4
    6561
    Correct
    Wrong
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Answer : 3. "3439"
Explanation :

Answer: C) 3439 Explanation: The numbers 0,1,2,3,4,5,6,7,8,9 are 10 in number while preparing telephone numbers any number can be used any number of times.   This can be done in 105ways, but '0' is there   So, the numbers starting with '0' are to be excluded is 94 numbers.    Total 5 digit telephone numbers = 105- 94 = 3439

Q: A shopkeeper sells one-third of his goods at a profit of 10%, another one-third at a profit of 20%, and the rest at a loss of 6%.What is his overall profit percentage ? 1862 0

  • 1
    6%
    Correct
    Wrong
  • 2
    8%
    Correct
    Wrong
  • 3
    10%
    Correct
    Wrong
  • 4
    12%
    Correct
    Wrong
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Answer : 2. "8%"
Explanation :

Answer: B) 8% Explanation: Let the shopkeeper buy 300g for Rs.300. Now he sells 100g for Rs.110, another 100g for Rs120, and the rest 100g for Rs94.    Therefore, the total amount he receives = Rs.110 + Rs.120 + Rs.94 = 324.    Therefore, the shopkeeper spends Rs.300 and gets back Rs.324.   Therefore, his profit percentage = 24300x100 % = 8%

Q: A retailer buys product from a shopkeeper at discount of 40% on the list price (marked price) and sells them to the customer at a discount of 25% on the list price.What is his profit percentage ? 2125 0

  • 1
    10%
    Correct
    Wrong
  • 2
    15%
    Correct
    Wrong
  • 3
    20%
    Correct
    Wrong
  • 4
    25%
    Correct
    Wrong
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Answer : 4. "25%"
Explanation :

Answer: D) 25% Explanation: Let the list price be Rs.100.    Therefore, the retailer is buying the products at Rs.60 and selling it to the customer at Rs.75, earning a profit of Rs.15.   Therefore, his percentage is = 1560x100 = 25%

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