Quantitative Aptitude Practice Question and Answer
8Q: In a class of 39 students the ratio of boys and girls is 2 : 1. Radhika ranks 15th among all the students from top and 8th among girls from bottom. How many boys are there below Radhika ? 4321 05b5cc705e4d2b4197774f1f3
5b5cc705e4d2b4197774f1f3- 19false
- 217true
- 311false
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Answer : 2. "17"
Explanation :
Answer: B) 17 Explanation: Total student= 39, boys : girls = 2:1, hence no of boys= 2/3(39)= 26num of girls= 1/3(39) = 13 , since radhika ranked 15 among 39 student from topand ranked 8 among girls from bottom , this means 7 girls are below radhika, rest 13-9= 5 girls are above her, now from 14 toper 5 are girls hence 14-5=9 boys.Hence num of boys below radhika are 26-9=17
Q: Amit can do a piece of work in 45 days, but Bharath can do the same work in 5 days less, than Amit, when working alone. Amit and Bharath both started the work together but Bharath left after some days and Amit finished the remaining work in 56 days with half of his efficiency but he did the work with Bharath with his complete efficiency. For how many days they had worked together? 4314 05b5cc7d0e4d2b419777511db
5b5cc7d0e4d2b419777511db- 16false
- 28true
- 39false
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Answer : 2. "8"
Explanation :
Answer: B) 8 Explanation: AmitBharatNo.of Days4540Efficiency2.22Percent(=145)2.5 Percent(=140) Amit did the work in 56 days = 56×145×2=2845 Therefore, Rest work 17/45 was done by Amit and Bharath = 174517360 = 8 days ( since Amit and Bharath do the work in one day = 145+140=17360)
Q: Ramesh and Dinesh can complete a work in 15 and 20 days respectively. Ramesh started working but after 5 days Dinesh replaced Ramesh. Find the share of Dinesh in Rs 15000 4300 05d1491b097a68b089a7aa717
5d1491b097a68b089a7aa717- 1Rs 5000false
- 2Rs 9000false
- 3Rs 10000true
- 4Rs 8000false
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Answer : 3. "Rs 10000"
Q: Amar can complete ¼ work in 3 days and Bhaskar can complete 1/6 th of the work in 4 days. If they work on it together, they get Rs 1800. Find the amount received by Amar. 4250 15d148fd797a68b089a7aa70d
5d148fd797a68b089a7aa70d- 1Rs 600false
- 2Rs 1000false
- 3Rs 1080false
- 4Rs 1200true
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Answer : 4. "Rs 1200"
Q: A and B runs around a circular track. A beats B by one round or 10 minutes. In this race, they had completed 4 rounds. If the race was only of one round, find the A's time over the course: 4236 05b5cc7d0e4d2b419777511e0
5b5cc7d0e4d2b419777511e0- 18 minfalse
- 27.5 mintrue
- 312.5 minfalse
- 412 minfalse
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Answer : 2. "7.5 min"
Explanation :
Answer: B) 7.5 min Explanation: B runs around the track in 10 min. i.e , Speed of B = 10 min per round Therefore, A beats B by 1 round Time taken by A to complete 4 rounds = Time taken by B to complete 3 rounds = 30 min Therefore, A's speed = 30/4 min per round = 7.5 min per round Hence, if the race is only of one round A's time over the course = 7 min 30 sec
Q: In one hour, a boat goes 12 km/hr along the stream and 6 km/hr against the stream. The speed of the boat in still water (in km/hr) is: 4228 05b5cc6bde4d2b4197774d8fc
5b5cc6bde4d2b4197774d8fc- 19true
- 28false
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Answer : 1. "9"
Explanation :
Answer: A) 9 Explanation: Speed in still water = Average of Speed in Upstream and speed in Downstream = 1/2 (12 + 6) kmph = 9 kmph.
Q: Solve the equation 122x+1 = 1 ? 4204 05b5cc6f4e4d2b4197774efd7
5b5cc6f4e4d2b4197774efd7- 1-1/2true
- 21/2false
- 31false
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Answer : 1. "-1/2"
Explanation :
Answer: A) -1/2 Explanation: Rewrite equation as 122x+1 = 120 Leads to 2x + 1 = 0 Solve for x : x = -1/2
Q: The marked price of an article is increased by 25% and the selling price is increased by 16.66%, then the amount of profit doubles. If the original marked price be Rs. 400 which is greater than the corresponding cost price by 33.33%, what is the increased selling price? 4203 05b5cc69ae4d2b4197774c755
5b5cc69ae4d2b4197774c755- 1Rs. 380false
- 2Rs. 420true
- 3Rs. 460false
- 4Rs. 440false
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Answer : 2. "Rs. 420"
Explanation :
Answer: B) Rs. 420 Explanation: As given in the question, Marked price is 25% more than the Cost price. => C.P of the article = 34 x 400 = 300 Now, Let the original S.P of the article be Rs. P Now the new S.P = P + 16.666 +13.333300 x P => S.P = 7P6 According to the question, 7P6 - 300 = 2P - 300 => 5P = 1800 => P = Rs. 360 Hence, the increased S.P = 360 x 7/6 = Rs. 420.