Quantitative Aptitude Practice Question and Answer
8Q: A and B runs around a circular track. A beats B by one round or 10 minutes. In this race, they had completed 4 rounds. If the race was only of one round, find the A's time over the course: 4091 05b5cc7d0e4d2b419777511e0
5b5cc7d0e4d2b419777511e0- 18 minfalse
- 27.5 mintrue
- 312.5 minfalse
- 412 minfalse
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Answer : 2. "7.5 min"
Explanation :
Answer: B) 7.5 min Explanation: B runs around the track in 10 min. i.e , Speed of B = 10 min per round Therefore, A beats B by 1 round Time taken by A to complete 4 rounds = Time taken by B to complete 3 rounds = 30 min Therefore, A's speed = 30/4 min per round = 7.5 min per round Hence, if the race is only of one round A's time over the course = 7 min 30 sec
Q: Solve the equation 122x+1 = 1 ? 4048 05b5cc6f4e4d2b4197774efd7
5b5cc6f4e4d2b4197774efd7- 1-1/2true
- 21/2false
- 31false
- 4-1false
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Answer : 1. "-1/2"
Explanation :
Answer: A) -1/2 Explanation: Rewrite equation as 122x+1 = 120 Leads to 2x + 1 = 0 Solve for x : x = -1/2
Q: The marked price of an article is increased by 25% and the selling price is increased by 16.66%, then the amount of profit doubles. If the original marked price be Rs. 400 which is greater than the corresponding cost price by 33.33%, what is the increased selling price? 4027 05b5cc69ae4d2b4197774c755
5b5cc69ae4d2b4197774c755- 1Rs. 380false
- 2Rs. 420true
- 3Rs. 460false
- 4Rs. 440false
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Answer : 2. "Rs. 420"
Explanation :
Answer: B) Rs. 420 Explanation: As given in the question, Marked price is 25% more than the Cost price. => C.P of the article = 34 x 400 = 300 Now, Let the original S.P of the article be Rs. P Now the new S.P = P + 16.666 +13.333300 x P => S.P = 7P6 According to the question, 7P6 - 300 = 2P - 300 => 5P = 1800 => P = Rs. 360 Hence, the increased S.P = 360 x 7/6 = Rs. 420.
Q: In one hour, a boat goes 12 km/hr along the stream and 6 km/hr against the stream. The speed of the boat in still water (in km/hr) is: 4023 05b5cc6bde4d2b4197774d8fc
5b5cc6bde4d2b4197774d8fc- 19true
- 28false
- 37false
- 47.5false
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Answer : 1. "9"
Explanation :
Answer: A) 9 Explanation: Speed in still water = Average of Speed in Upstream and speed in Downstream = 1/2 (12 + 6) kmph = 9 kmph.
Q: In how many years, Rs. 200 will produce the same interest @ 5 % as Rs. 900 produce in 2 years @ 3 ½ % ? 3996 05b5cc6dbe4d2b4197774e909
5b5cc6dbe4d2b4197774e909- 15.2 yrsfalse
- 27 yrsfalse
- 37.9 yrsfalse
- 46.3 yrstrue
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Answer : 4. "6.3 yrs"
Explanation :
Answer: D) 6.3 yrs Explanation: P = Rs. 900, R = 3 ½ % = 7/2 %, T = 2 years. Therefore, S.I. = PTR/100 S.I. = Rs. (900 x 7/2 x 2/100) = Rs. 63 Now, P = Rs. 200, S.I. = Rs. 63, R = 5 % Time = ((100 x 63) / (200 x 5) ) years = 6.3 years.
Q: A boatman can row 96 km downstream in 8 hr. If the speed of the current is 4 km/hr, then find in what time he will be able to cover 8 km upstream ? 3989 05b5cc6e9e4d2b4197774ede3
5b5cc6e9e4d2b4197774ede3- 11.5 hrsfalse
- 21 hrsfalse
- 32.5 hrsfalse
- 42 hrstrue
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Answer : 4. "2 hrs"
Explanation :
Answer: D) 2 hrs Explanation: Speed in downstream = 96/8 = 12 kmph Speed of current = 4 km/hr Speed of the boatman in still water = 12 – 4 = 8 kmph Speed in upstream = 8 – 4 = 4 kmph Time taken to cover 8 km upstream = 8/4 = 2 hours.
Q: The product of a number and its multiplicative inverse is 3963 05b5cc64de4d2b4197774bc70
5b5cc64de4d2b4197774bc70- 11true
- 20false
- 3-1false
- 4Infinityfalse
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Answer : 1. "1"
Explanation :
Answer: A) 1 Explanation: The mutiplicative inverse of a number is nothing but a reciprocal of a number. Now, the product of a number and its multiplicative inverse is always equal to 1. For example : Let the number be 15 Multiplicative inverse of 15 = 1/15 The product of a number and its multiplicative inverse is = 15 x 1/15 = 1.
Q: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs. 5000 ? 3961 05b5cc709e4d2b4197774f294
5b5cc709e4d2b4197774f294- 1Rs. 5500false
- 2Rs. 6000true
- 3Rs. 6200false
- 4Rs. 6350false
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Answer : 2. "Rs. 6000"
Explanation :
Answer: B) Rs. 6000 Explanation: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs 5000 ?Ratio of increase of wages = 22:25Ratio of decrease of labourers = 15:11Compound ratio of wages of labourers = 22 x 15 : 25 x 11 = 330:275Final bill = Rs. 5000For 275 ratio wages = Rs. 5000For 1 ratio wages = 5000/275For 330 ratio wages = 5000/275 x 330 = Rs. 6000