Quantitative Aptitude Practice Question and Answer
8Q: Rajan's present age is three times his daughter's and nine-thirteenth of his mother's present age. The sum of the present ages of all three of them is 125 years. What is the difference between the present ages of Rajan's daughter and Rajan's mather ? 2292 05b5cc72ce4d2b4197774f773
5b5cc72ce4d2b4197774f773- 132 yearsfalse
- 248 yearsfalse
- 362 yearsfalse
- 450 yearstrue
- Show Answer
- Workspace
- SingleChoice
Answer : 4. "50 years"
Explanation :
Answer: D) 50 years Explanation: Let Rajan's present age be 'x' years.=> Then his daughter's present age is = x/3 years.His mother's present age = 13x/9 yearsNow, according to the question,x + x/3 + 13x/9 = 125=> x = 125x9/25 = 45Therefore, required difference = 13x/9 - x/3 = 13x - 3x/9 = 10x/9=> 10 x 45/9 = 50 years.
Q: A,B and C enter into a partnership in the ratio 72:43:65. After 4 months, A increases his share by 50%. If the total profit at the end of one year be Rs. 21600, then B's share in the profit is : 2283 05b5cc783e4d2b419777501ec
5b5cc783e4d2b419777501ec- 1Rs. 4000true
- 2Rs. 6000false
- 3Rs. 9000false
- 4Rs. 3000false
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "Rs. 4000"
Explanation :
Answer: A) Rs. 4000 Explanation: Given ratio of initial investments = 72:43:65 = 105 : 40 : 36. Let the initial investments be 105x, 40x and 36x. ∴A:B:C = 105x×4 + 150100×105x×8 : 40x×12 : 36x×12 = 1680x : 480x : 432x = 35 : 10 : 9. Hence, B's share = 21600×1054 = Rs. 4000.
Q: 7, 11, 19, 35, ? Find the next number in the given number series? 2280 05b5cc6ace4d2b4197774d0bb
5b5cc6ace4d2b4197774d0bb- 1131false
- 294false
- 383false
- 467true
- Show Answer
- Workspace
- SingleChoice
Answer : 4. "67"
Explanation :
Answer: D) 67 Explanation: Here the given series 7, 11, 19, 35, ? follows a pattern that (x 2 - 3) i.e, 7 7 x 2 - 3 = 11 11 x 2 - 3 = 19 19 x 2 - 3 = 35 35 x 2 - 3 = 67 67 x 2 - 3 = 131 Hence the next number in the given number series is 67.
Q: The ratio between boys and girl’s in a school is 4:6 respectively. If the number of boys is increased by 200 the ratio becomes 5:6 respectively. How many girls are there in the school? 2278 05d1b06bf1fc62311c773685b
5d1b06bf1fc62311c773685b- 11200true
- 2800false
- 31000false
- 4500false
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "1200"
Q: A certain sum of money is invested for one year at a certain rate of simple interest. If the rate of interest is 3% higher, then the invest earned will be 25% more than the interest earned earlier. What is the earlier rate of interest ? 2272 05b5cc6eee4d2b4197774eeeb
5b5cc6eee4d2b4197774eeeb- 14% p.a.false
- 26% p.a.false
- 38% p.a.false
- 412% p.a.true
- Show Answer
- Workspace
- SingleChoice
Answer : 4. "12% p.a."
Explanation :
Answer: D) 12% p.a. Explanation: If the interest earned is 25% more than the earlier interest then the rate of interest also should be 25% higher than the earlier rate. Let the earlier rate of interest be x%. Now it will be (x + 3)% % increase = (x + 3) - x/x * 100 = 25=> x = 12%
Q: Find the odd man out from the given alternatives ? 2271 05b5cc6cee4d2b4197774e232
5b5cc6cee4d2b4197774e232- 197false
- 2233false
- 3437true
- 4599false
- Show Answer
- Workspace
- SingleChoice
Answer : 3. "437"
Explanation :
Answer: C) 437 Explanation: Except 437 all others are prime numbers.
Q: On selling 36 oranges one incurs a loss equal to selling Price of 4 oranges. What will be the loss%? 2264 05d133058925caa2d5bbbff6b
5d133058925caa2d5bbbff6b- 110%true
- 234%false
- 313%false
- 414%false
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "10%"
Q: Total number of students in 3 classes of a school is 333 . The number of students in class 1 and 2 are in 3:5 ratio and 2 and 3 class are 7:11 ratio . What is the strength of class that has highest number of students ? 2261 05b5cc72ce4d2b4197774f7a6
5b5cc72ce4d2b4197774f7a6- 1125false
- 2155false
- 3135false
- 4165true
- Show Answer
- Workspace
- SingleChoice
Answer : 4. "165"
Explanation :
Answer: D) 165 Explanation: Ratio C1:C2 = 3:5 and C2:C3 = 7:11So C1:C2:C3 = 21 : 35 : 55Let the strength of three classes are 21x, 35x and 55x respectively, then Given that 21x + 35x + 55x = 333=> 111x = 333 or x=3So strength of the class with highest number of students =55x = 55x3 = 165.