Quantitative Aptitude Practice Question and Answer
8Q: A trader mixes 36 kg of rice at Rs. 20 per kg with 14 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is: 2195 05b5cc76ae4d2b4197774fe4a
5b5cc76ae4d2b4197774fe4a- 125%false
- 221.14%false
- 322.54%true
- 427.32%false
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Answer : 3. "22.54%"
Explanation :
Answer: C) 22.54% Explanation: C.P. of 50 kg rice = Rs. (36 x 20 + 14 x 36) = Rs. (720 + 504) = Rs.1224. S.P. of 56 kg rice = Rs. (50 x 30) = Rs.1500. Profit = 1500 - 1224 = Rs.276 Profit % = ProfitC.P×100 = 2761224×100 = 22.54%.
Q: P, Q, R, S, T and U are six consecutive odd numbers and their average is 52. What is the product of P and U ? 2193 05b5cc6b9e4d2b4197774d711
5b5cc6b9e4d2b4197774d711- 12212false
- 22154false
- 32349false
- 42679true
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Answer : 4. "2679"
Explanation :
Answer: D) 2679 Explanation: Let x, x+2, x+4, x+6, x+8 and x+10 are six consecutive odd numbers. Given that their average is 52 Then, x + x+2 + x+4 + x+6 + x+8 + x+10 = 52×6 6x + 30 = 312 x = 47 So Product = 47 × 57 = 2679
Q: On 24th Nov, 2007 Thursday falls. What day of the week was it on 10th Nov, 2006 ? 2192 05b5cc75ce4d2b4197774fc20
5b5cc75ce4d2b4197774fc20- 1Wednesdaytrue
- 2Tuesdayfalse
- 3Fridayfalse
- 4Thursdayfalse
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Answer : 1. "Wednesday"
Explanation :
Answer: A) Wednesday Explanation: The year 2006 is an ordinary year. So, it has 1 odd day.So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.But, 24th Nov, 2007 is Thursday. 24 - 10 = 14 days. Therefore, 2 weeks ago it is same day. Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.
Q: Out of 135 applicants for a post, 60 are graduates and 80 have experience. What is the ratio of minimum to maximum numberof graduates having experience? 2190 05b5cc774e4d2b41977750066
5b5cc774e4d2b41977750066- 112:1false
- 25:1false
- 31:5false
- 41:12true
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Answer : 4. "1:12"
Explanation :
Answer: D) 1:12 Explanation: Given total applicants = 135Given graduates are G=60 Otherthan graduates=135-60 = 75Given experienced candidates = 801) For maximum number of graduates have experience Total graduates to have experience = 60 2) For minimum number of graduates have experience Remaining after taking other than graduates in experience= 80-75 = 5
Q: A retailer buys product from a shopkeeper at discount of 40% on the list price (marked price) and sells them to the customer at a discount of 25% on the list price.What is his profit percentage ? 2190 05b5cc7a5e4d2b4197775066f
5b5cc7a5e4d2b4197775066f- 110%false
- 215%false
- 320%false
- 425%true
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Answer : 4. "25%"
Explanation :
Answer: D) 25% Explanation: Let the list price be Rs.100. Therefore, the retailer is buying the products at Rs.60 and selling it to the customer at Rs.75, earning a profit of Rs.15. Therefore, his percentage is = 1560x100 = 25%
Q: In a hostel, there was food for 1000 students for one month. After 10 days, 1000 more students joined the hostel. How long would the students be able to carry on with the remaining food? 2181 05b5cc774e4d2b41977750025
5b5cc774e4d2b41977750025- 110 daystrue
- 215 daysfalse
- 320 daysfalse
- 45 daysfalse
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Answer : 1. "10 days"
Explanation :
Answer: A) 10 days Explanation: After 10 days, the remaining food would be sufficient for the 1000 students for 20 more days -->If 1000 more students are added, it shall be sufficient for only 10 days (as the no. of students is doubled, the days are halved).
Q: How much does a clock lose per day, if its hands coincide ever 65 minutes ? 2179 05b5cc6f8e4d2b4197774f077
5b5cc6f8e4d2b4197774f077- 11440/143 minfalse
- 2184/13 minfalse
- 31425/18 mintrue
- 4541/9 minfalse
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Answer : 3. "1425/18 min"
Explanation :
Answer: C) 1425/18 min Explanation: 55 min. spaces are covered in 60 min.60 min. spaces are covered in ((60/55) x 60) min = 720/11 min.Loss in 65 min. = (720/11 - 65 ) = 5/11Loss in 24 hrs = (5/11 x 1/65 x 24 x 60)min = 1440/143 min.
Q: Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each gentleman received twice the paise as each lady received. Find the number of gentlemen in the family? 2177 05b5cc67be4d2b4197774c1f0
5b5cc67be4d2b4197774c1f0- 123true
- 292false
- 348false
- 452false
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Answer : 1. "23"
Explanation :
Answer: A) 23 Explanation: Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115 ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23 Hence, required number of gentlemen in the family = x = 23.