Quantitative Aptitude Practice Question and Answer
8Q: A retailer buys product from a shopkeeper at discount of 40% on the list price (marked price) and sells them to the customer at a discount of 25% on the list price.What is his profit percentage ? 2212 05b5cc7a5e4d2b4197775066f
5b5cc7a5e4d2b4197775066f- 110%false
- 215%false
- 320%false
- 425%true
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Answer : 4. "25%"
Explanation :
Answer: D) 25% Explanation: Let the list price be Rs.100. Therefore, the retailer is buying the products at Rs.60 and selling it to the customer at Rs.75, earning a profit of Rs.15. Therefore, his percentage is = 1560x100 = 25%
Q: A student can divide her books into groups of 5, 9 and 13. what is the smallest possible number of the books ? 2212 05b5cc74ae4d2b4197774fab3
5b5cc74ae4d2b4197774fab3- 1487false
- 2585true
- 3635false
- 4705false
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Answer : 2. "585"
Explanation :
Answer: B) 585 Explanation: The smallest possible number of books = L.C.M of 5, 9 and 13.Therefore, L.C.M of 5,9 and 13 is = 5 x 9 x 13 = 585.
Q: Out of 135 applicants for a post, 60 are graduates and 80 have experience. What is the ratio of minimum to maximum numberof graduates having experience? 2212 05b5cc774e4d2b41977750066
5b5cc774e4d2b41977750066- 112:1false
- 25:1false
- 31:5false
- 41:12true
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Answer : 4. "1:12"
Explanation :
Answer: D) 1:12 Explanation: Given total applicants = 135Given graduates are G=60 Otherthan graduates=135-60 = 75Given experienced candidates = 801) For maximum number of graduates have experience Total graduates to have experience = 60 2) For minimum number of graduates have experience Remaining after taking other than graduates in experience= 80-75 = 5
Q: On 24th Nov, 2007 Thursday falls. What day of the week was it on 10th Nov, 2006 ? 2211 05b5cc75ce4d2b4197774fc20
5b5cc75ce4d2b4197774fc20- 1Wednesdaytrue
- 2Tuesdayfalse
- 3Fridayfalse
- 4Thursdayfalse
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Answer : 1. "Wednesday"
Explanation :
Answer: A) Wednesday Explanation: The year 2006 is an ordinary year. So, it has 1 odd day.So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.But, 24th Nov, 2007 is Thursday. 24 - 10 = 14 days. Therefore, 2 weeks ago it is same day. Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.
Q: How much does a clock lose per day, if its hands coincide ever 65 minutes ? 2205 05b5cc6f8e4d2b4197774f077
5b5cc6f8e4d2b4197774f077- 11440/143 minfalse
- 2184/13 minfalse
- 31425/18 mintrue
- 4541/9 minfalse
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Answer : 3. "1425/18 min"
Explanation :
Answer: C) 1425/18 min Explanation: 55 min. spaces are covered in 60 min.60 min. spaces are covered in ((60/55) x 60) min = 720/11 min.Loss in 65 min. = (720/11 - 65 ) = 5/11Loss in 24 hrs = (5/11 x 1/65 x 24 x 60)min = 1440/143 min.
Q: Two persons Shyam and Rahim can do a job in 32 days together. Rahim can do the same job in 48 days alone. They started working together and after working 8 days Rahim is replaced by a third person Ram whose efficiency is half that of Rahim. Find in how many days the remaining work will be completed by both Shyam and Ram together? 2199 05b5cc6a3e4d2b4197774cc20
5b5cc6a3e4d2b4197774cc20- 116 daysfalse
- 272/5 daystrue
- 315 daysfalse
- 496/5 daysfalse
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Answer : 2. "72/5 days"
Explanation :
Answer: B) 72/5 days Explanation: Work done by Shyam and Rahim in 8 days = 8/32 = 1/4 Remaining work to be done by Shyam and Ram = 1 - 1/4 = 3/4 Given efficieny of Ram is half of Rahim i.e, as Rahim can do the work in 48 days, Ram can do the work in 24 days. One day work of Ram and Shyam = (1/32 - 1/48) + 1/24 = 5/96 Hence, the total work can be done by Shyam and Ram together in 96/5 days. Therefore, remaining work 3/4 can be done by them in 3/4 x 96/5 = 72/5 = 14.4 days.
Q: How many remainders are possible if 16n is divided by 9 for any positive integral value of n ? 2198 05b5cc77ae4d2b41977750151
5b5cc77ae4d2b41977750151- 11false
- 22false
- 33true
- 44false
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Answer : 3. "3"
Explanation :
Answer: C) 3 Explanation: When 16nis divided by 9, we have 1619, remainder = 7 1629, remainder = 4 1639, remainder = 1 1649, remainder = 7 1659, remainder = 4 1669, remainder = 1 So, we have cyclicity of 3 factors i.e 7,4,1. Hence only 3 remainders are possible.
Q: Karthik read 613 th of a book in 1st week and 59 th of the remaining book in 2nd week. If there were 100 pages unread after 2nd week, how many pages were there in the book ? 2197 05b5cc76fe4d2b4197774ff76
5b5cc76fe4d2b4197774ff76- 1404false
- 2415false
- 3418true
- 4420false
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Answer : 3. "418"
Explanation :
Answer: C) 418 Explanation: Let the total book be 1 Then, in the 1st week 613th of book is read i.e remaining pages = 1-613=713 in 2nd week he read 59th of it i.e 59×713=35117Remaining pages after 2nd week = 713-35117=28117 But given remaining pages after 2nd week = 100 28x117=100 --> x = 418 The total pages in the book are 418