Quantitative Aptitude Practice Question and Answer
8Q: A secret can be told to only 3 persons in 3 minutes. Each person in turn tells 3 other persons in the next 3 minutes and the processes continues accordingly. In 30 minutes how many persons can be told this secret in this way ? 2042 05b5cc741e4d2b4197774f99a
5b5cc741e4d2b4197774f99a- 188572true
- 277854false
- 399584false
- 455654false
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Answer : 1. "88572"
Explanation :
Answer: A) 88572 Explanation: Given a secret is told to 3 persons in 3 minutes.And if the process continues with each person saying 3 other persons,In 30 minutes => the rocess for 10 times because each person time is 3 minutes.Required number of persons = 3 + 32 + 33 + .... + 39 + 310 Now it forms a geometric progression, Sum to n terms is S = arn - 1r - 1 Here a = 3, r = 3 => 59048 x 3 /2 = 88572.
Q: The calendar for the year 2018 will be the same for the year 2041 05b5cc6ace4d2b4197774d096
5b5cc6ace4d2b4197774d096- 12023false
- 22027false
- 32029true
- 42022false
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Answer : 3. "2029"
Explanation :
Answer: C) 2029 Explanation: How to find the years which have the same Calendars : Leap year calendar repeats every 28 years. Here 28 is distributed as 6 + 11 + 11. Rules: a) If given year is at 1st position after Leap year then next repeated calendar year is Givenyear+6. b) If given year is at 2nd position after Leap year then next repeated calendar year is Givenyear+11. c) If given year is at 3rd position after Leap year then next repeated calendar year is Givenyear+11. Now, the given year is 2018 We know that 2016 is a Leap year. 2016 2017 2018 2019 2020 Lp Y 1st 2nd 3rd Lp Y Here 2018 is at 2 nd position after the Leap year. According to rule b) the calendar of 2018 is repeated for the year is 2018 + 11 = 2029.
Q: 82.5% of 2360? 2036 05b5cc60ae4d2b4197774b5a1
5b5cc60ae4d2b4197774b5a1- 11960false
- 21954false
- 31947true
- 41931false
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Answer : 3. "1947"
Explanation :
Answer: C) 1947 Explanation: Given 82.5% of 2360 82.5100 x 2360 = 0.825 x 2360 = 1947
Q: In a hostel, there was food for 1000 students for one month. After 10 days, 1000 more students joined the hostel. How long would the students be able to carry on with the remaining food? 2034 05b5cc774e4d2b41977750025
5b5cc774e4d2b41977750025- 110 daystrue
- 215 daysfalse
- 320 daysfalse
- 45 daysfalse
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Answer : 1. "10 days"
Explanation :
Answer: A) 10 days Explanation: After 10 days, the remaining food would be sufficient for the 1000 students for 20 more days -->If 1000 more students are added, it shall be sufficient for only 10 days (as the no. of students is doubled, the days are halved).
Q: If 15% of x = 20% of y, then x:y is ___? 2034 05b5cc6bde4d2b4197774d929
5b5cc6bde4d2b4197774d929- 14:3true
- 25:4false
- 34:5false
- 43:4false
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Answer : 1. "4:3"
Explanation :
Answer: A) 4:3 Explanation: Given 15% of x = 20% of y => 15x = 20y => x/y = 20/15 => x : y = 4 : 3
Q: A,B and C enter into a partnership in the ratio 72:43:65. After 4 months, A increases his share by 50%. If the total profit at the end of one year be Rs. 21600, then B's share in the profit is : 2033 05b5cc783e4d2b419777501ec
5b5cc783e4d2b419777501ec- 1Rs. 4000true
- 2Rs. 6000false
- 3Rs. 9000false
- 4Rs. 3000false
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Answer : 1. "Rs. 4000"
Explanation :
Answer: A) Rs. 4000 Explanation: Given ratio of initial investments = 72:43:65 = 105 : 40 : 36. Let the initial investments be 105x, 40x and 36x. ∴A:B:C = 105x×4 + 150100×105x×8 : 40x×12 : 36x×12 = 1680x : 480x : 432x = 35 : 10 : 9. Hence, B's share = 21600×1054 = Rs. 4000.
Q: What time will it be 18 hours from now in India, if in the USA it is 4:15 AM? (Hint : IST = US + 9:30 hrs) 2031 05b5cc699e4d2b4197774c6dc
5b5cc699e4d2b4197774c6dc- 11:45 in the afternoonfalse
- 27:45 in the eveningfalse
- 37:45 in the next morningtrue
- 41:45 in the next morningfalse
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Answer : 3. "7:45 in the next morning"
Explanation :
Answer: C) 7:45 in the next morning Explanation: We know that the time difference between India and USA is 9 hrs 30 min. India is 9:30 hrs ahead of USA. Time in India = 4:15 + 9:30 = 13:45 PM. Required Time after 18 hrs = 13:45 + 18 hrs = 7:45 AM. Hence it is 7:45 AM on the next morning.
Q: A box contains 4 different black balls, 3 different red balls and 5 different blue balls. In how many ways can the balls be selected if every selection must have at least 1 black ball and one red ball ? 2025 05b5cc6f4e4d2b4197774f004
5b5cc6f4e4d2b4197774f004- 124 - 1false
- 22425-1false
- 3(24-1)(23-1)25true
- 4Nonefalse
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Answer : 3. "(24-1)(23-1)25"
Explanation :
Answer: C) C Explanation: It is explicitly given that all the 4 black balls are different, all the 3 red balls are different and all the 5 blue balls are different. Hence this is a case where all are distinct objects. Initially let's find out the number of ways in which we can select the black balls. Note that at least 1 black ball must be included in each selection. Hence, we can select 1 black ball from 4 black ballsor 2 black balls from 4 black balls.or 3 black balls from 4 black balls.or 4 black balls from 4 black balls. Hence, number of ways in which we can select the black balls = 4C1 + 4C2 + 4C3 + 4C4= 24-1 ........(A) Now let's find out the number of ways in which we can select the red balls. Note that at least 1 red ball must be included in each selection. Hence, we can select 1 red ball from 3 red ballsor 2 red balls from 3 red ballsor 3 red balls from 3 red balls Hence, number of ways in which we can select the red balls= 3C1 + 3C2 + 3C3=23-1........(B) Hence, we can select 0 blue ball from 5 blue balls (i.e, do not select any blue ball. In this case, only black and red balls will be there)or 1 blue ball from 5 blue ballsor 2 blue balls from 5 blue ballsor 3 blue balls from 5 blue ballsor 4 blue balls from 5 blue ballsor 5 blue balls from 5 blue balls. Hence, number of ways in which we can select the blue balls= 5C0 + 5C1 + 5C2 + … + 5C5= 25..............(C) From (A), (B) and (C), required number of ways= 2524-123-1