Quantitative Aptitude Practice Question and Answer
8Q: A sum of money at simple interest amounts to Rs. 415 in 2 years and to Rs. 514 in 4 years. The sum is ? 2491 05b5cc6d7e4d2b4197774e6f6
5b5cc6d7e4d2b4197774e6f6- 1Rs. 316true
- 2Rs. 251false
- 3Rs. 154false
- 4Rs. 294false
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Answer : 1. "Rs. 316"
Explanation :
Answer: A) Rs. 316 Explanation: S.I. for 2 years = (514 - 415) = Rs. 99S.I. for 1 year = 99/2 Principal = (415 - 99) = Rs. 316.
Q: A is 3 times faster than B. If A can finish a work 32 days less than that of B, find the number of days need to finish the work if both are working together? 2491 05b5cc754e4d2b4197774fb62
5b5cc754e4d2b4197774fb62- 112 daystrue
- 224 daysfalse
- 332 daysfalse
- 416 daysfalse
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Answer : 1. "12 days"
Explanation :
Answer: A) 12 days Explanation: It is given that efficiency ratio =3:1 so time ratio will be 1:3 (since work is same) Also given that time diff = 32 days. ratio difference = 3-1 =2 2 ratio = 32 days 1 ratio = 16 days. So A will alone finish it in 16 days and B will finish it in 16*3 = 48 days. Total work = LCM of 16 and 48 = 48. Total time = Total work/Total efficiency ie; 48/4= 12 days.
Q: 40% of 265 + 35% of 180 = 50% of ? 2490 05b5cc75ce4d2b4197774fc57
5b5cc75ce4d2b4197774fc57- 1383false
- 2338true
- 384.5false
- 4253.5false
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Answer : 2. "338"
Explanation :
Answer: B) 338 Explanation: We know that 40% = 25 40% of 265 + 35% of 180 = 50% ? 25 x 265 + 35% of 180 = 50% ? We know that (35% of 180 = 180% of 35) & 180% = 95 25 x 265 + 95 x 35 = 50% ? 106 + 63 = 50% ? ?= 2 x 169 = 338.
Q: The ratio of Pens and Pencils in a shop is 3 : 2 respectively. The average number of Pens and Pencils is 180. What is the number of Pencils in the shop? 2472 05b5cc6a7e4d2b4197774ce18
5b5cc6a7e4d2b4197774ce18- 1444false
- 2344false
- 3244false
- 4144true
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Answer : 4. "144"
Explanation :
Answer: D) 144 Explanation: Given ratio of pens and pencils = 3 :2 Number of Pens = 3x Number of Pencils = 2x Average number of pencils & Pens = 3x + 2x2 = 180 5x = 360 => x = 72 Hence, the number of pencils = 2x = 72 x 2 = 144.
Q: A box contains 4 different black balls, 3 different red balls and 5 different blue balls. In how many ways can the balls be selected if every selection must have at least 1 black ball and one red ball ? 2470 05b5cc6f4e4d2b4197774f004
5b5cc6f4e4d2b4197774f004- 124 - 1false
- 22425-1false
- 3(24-1)(23-1)25true
- 4Nonefalse
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Answer : 3. "(24-1)(23-1)25"
Explanation :
Answer: C) C Explanation: It is explicitly given that all the 4 black balls are different, all the 3 red balls are different and all the 5 blue balls are different. Hence this is a case where all are distinct objects. Initially let's find out the number of ways in which we can select the black balls. Note that at least 1 black ball must be included in each selection. Hence, we can select 1 black ball from 4 black ballsor 2 black balls from 4 black balls.or 3 black balls from 4 black balls.or 4 black balls from 4 black balls. Hence, number of ways in which we can select the black balls = 4C1 + 4C2 + 4C3 + 4C4= 24-1 ........(A) Now let's find out the number of ways in which we can select the red balls. Note that at least 1 red ball must be included in each selection. Hence, we can select 1 red ball from 3 red ballsor 2 red balls from 3 red ballsor 3 red balls from 3 red balls Hence, number of ways in which we can select the red balls= 3C1 + 3C2 + 3C3=23-1........(B) Hence, we can select 0 blue ball from 5 blue balls (i.e, do not select any blue ball. In this case, only black and red balls will be there)or 1 blue ball from 5 blue ballsor 2 blue balls from 5 blue ballsor 3 blue balls from 5 blue ballsor 4 blue balls from 5 blue ballsor 5 blue balls from 5 blue balls. Hence, number of ways in which we can select the blue balls= 5C0 + 5C1 + 5C2 + … + 5C5= 25..............(C) From (A), (B) and (C), required number of ways= 2524-123-1
Q: If log72 = m, then log4928 is equal to ? 2469 05b5cc761e4d2b4197774fd5d
5b5cc761e4d2b4197774fd5d- 11/(1+2m)false
- 2(1+2m)/2true
- 32m/(2m+1)false
- 4(2m+1)/2mfalse
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Answer : 2. "(1+2m)/2"
Explanation :
Answer: B) (1+2m)/2 Explanation: log4928 = 12log77×4 = 12+122log72= 12+log72= 12 + m= 1+2m2.
Q: A trader mixes 36 kg of rice at Rs. 20 per kg with 14 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is: 2466 05b5cc76ae4d2b4197774fe4a
5b5cc76ae4d2b4197774fe4a- 125%false
- 221.14%false
- 322.54%true
- 427.32%false
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Answer : 3. "22.54%"
Explanation :
Answer: C) 22.54% Explanation: C.P. of 50 kg rice = Rs. (36 x 20 + 14 x 36) = Rs. (720 + 504) = Rs.1224. S.P. of 56 kg rice = Rs. (50 x 30) = Rs.1500. Profit = 1500 - 1224 = Rs.276 Profit % = ProfitC.P×100 = 2761224×100 = 22.54%.
Q: What is the ratio of 18 minutes to one hour ? 2464 05b5cc6bfe4d2b4197774da24
5b5cc6bfe4d2b4197774da24- 11/5false
- 23/4false
- 31/7false
- 43/10true
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Answer : 4. "3/10"
Explanation :
Answer: D) 3/10 Explanation: One hour = 60 min 18/60 = 3/10

