Quantitative Aptitude Practice Question and Answer
8Q: A sequence of natural number 2,3,5,6,10. Such that no square and no cube occurs in the term. Find the 300th term of sequence ? 1039 05b5cc709e4d2b4197774f29e
5b5cc709e4d2b4197774f29e- 1322false
- 2319false
- 3321false
- 4320true
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Answer : 4. "320"
Explanation :
Answer: D) 320 Explanation: 1 to 300 = 300 numbers squares btwn 1 to 300 = 1,4,9,16,25,36,49.....289 i.e, total 17cubes = 1,8,27,64,125,216 i.e, 5 now 1 and 64 are common so total numbers that should be removed ( 17+5-2= 20 )total 20 term removed so 300th term would be 320
Q: Sambhu buys rice at Rs. 10/kg and puts a price tag on it so as to earn a profit of 20%. However, his faulty balance shows 1000 gm when it is actually 800 gm. What is his actual gain percentage ? 1312 05b5cc709e4d2b4197774f299
5b5cc709e4d2b4197774f299- 150%true
- 225%false
- 375%false
- 460%false
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Answer : 1. "50%"
Explanation :
Answer: A) 50% Explanation: CP of 1000gm = Rs. 10SP of 800gm = Rs. 12SP of 1000gm =12x1000/800 = Rs. 15 Now take 1000gm as reference to calculate profit.Profit=SP-CP=15-10=Rs. 5Profit % = 5x100/10 = 50%
Q: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs. 5000 ? 3966 05b5cc709e4d2b4197774f294
5b5cc709e4d2b4197774f294- 1Rs. 5500false
- 2Rs. 6000true
- 3Rs. 6200false
- 4Rs. 6350false
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Answer : 2. "Rs. 6000"
Explanation :
Answer: B) Rs. 6000 Explanation: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs 5000 ?Ratio of increase of wages = 22:25Ratio of decrease of labourers = 15:11Compound ratio of wages of labourers = 22 x 15 : 25 x 11 = 330:275Final bill = Rs. 5000For 275 ratio wages = Rs. 5000For 1 ratio wages = 5000/275For 330 ratio wages = 5000/275 x 330 = Rs. 6000
Q: What was the day on 2nd Jan 1901 ? 3629 05b5cc709e4d2b4197774f28f
5b5cc709e4d2b4197774f28f- 1Tuesdayfalse
- 2Wednesdaytrue
- 3Mondayfalse
- 4Thursdayfalse
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Answer : 2. "Wednesday"
Explanation :
Answer: B) Wednesday Explanation: 2nd Jan 1901 means(1900 years and 2 day)Now, 1600 years have 0 odd day300 years have 1 odd day2 days has 2 odd dayTotal no. of odd days = 0 + 1 + 2 = 3 daysHence, the day on 2nd Jan 1901 was Wednesday.
Q: There are 41 students in a class, number of girls is one more than number of guys. we need to form a team of four students. all four in the team cannot be from same gender. number of girls and guys in the team should NOT be equal. How many ways can such a team be made ? 1501 05b5cc709e4d2b4197774f262
5b5cc709e4d2b4197774f262- 149450false
- 250540true
- 346587false
- 452487false
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Answer : 2. "50540"
Explanation :
Answer: B) 50540 Explanation: Given G + B= 41 and B = G-1 Hence, G = 21 and B = 20Now we have 2 options, 1G and 3M (or) 3G and 1M(2G and 2M or 0G and 4M or 4G and oM are not allowed), Total : C121×C320+C321×C120= 50540 ways.
Q: The difference of two numbers is 14. Their LCM and HCF are 441 and 7. Find the two numbers ? 2631 05b5cc709e4d2b4197774f267
5b5cc709e4d2b4197774f267- 163 and 49true
- 264 and 48false
- 362 and 46false
- 464 and 49false
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Answer : 1. "63 and 49"
Explanation :
Answer: A) 63 and 49 Explanation: Since their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y Difference = 14 => 7x - 7y = 14=> x - y = 2 product of numbers = product of their hcf and lcm=> 7x * 7y = 441 * 7=> x * y = 63 Now, we havex * y = 63 , x - y = 2=> x = 9 , y = 7 The numbers are 7x and 7y=> 63 and 49
Q: If 1/a+1/b+1/c = 1/(a+b+c) where a+b+c not equals '0', abc not equals '0', What is the value of (a+b) (b+c) (a+c) ? 1340 05b5cc709e4d2b4197774f258
5b5cc709e4d2b4197774f258- 13false
- 22false
- 31false
- 40true
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Answer : 4. "0"
Explanation :
Answer: D) 0 Explanation: Let assume the value of a,b &c that will satisfy the equation.so a=1,b=1,c= -1 or a=1,b= -1 &c=1 or a= -1,b=1,c=1here all three cases satisfy the equationassume any one a=1,b=1,c= -1 Hence (a+b)(b+c)(c+a)=(1+1)(1-1)(-1+1) = 0
Q: There are 3 bags, in 1st there are 9 Mangoes, in 2nd 8 apples & in 3rd 6 bananas. There are how many ways you can buy one fruit if all the mangoes are identical, all the apples are identical, & also all the Bananas are identical ? 1297 05b5cc705e4d2b4197774f253
5b5cc705e4d2b4197774f253- 123true
- 2432false
- 322false
- 4431false
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Answer : 1. "23"
Explanation :
Answer: A) 23 Explanation: As in this problem , buying any fruit is different case , as buying apple is independent from buying banana. so ADDITION rule will be used. C19+C18+C16 = 23 will be answer.