Quantitative Aptitude Practice Question and Answer
8Q: A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most ? 1527 05b5cc6e1e4d2b4197774ebde
5b5cc6e1e4d2b4197774ebde- 1215true
- 2268false
- 3254false
- 4216false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "215"
Explanation :
Answer: A) 215 Explanation: Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 x 6 x 6 = 216. Of these attempts, one of them is a successful attempt. Maximum number of unsuccessful attempts = 216 - 1 = 215.
Q: Rs.1200 divided among P, Q and R. P gets half of the total amount received by Q and R. Q gets one-third of the total amount received by P and R. Find the amount received by R ? 4694 05b5cc6e1e4d2b4197774ebd9
5b5cc6e1e4d2b4197774ebd9- 1Rs. 1100false
- 2Rs. 500true
- 3Rs. 1200false
- 4Rs. 700false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "Rs. 500"
Explanation :
Answer: B) Rs. 500 Explanation: Let the amounts to be received by P, Q and R be p, q and r.p + q + r = 1200p = 1/2 (q + r) => 2p = q + r Adding 'p' both sides, 3p = p + q + r = 1200=> p = Rs.400 q = 1/3 (p + r) => 3q = p + r Adding 'q' both sides, 4q = p + q + r = 1200=> q = Rs.300 r = 1200 - (p + q) => r = Rs.500.
Q: Find the odd one out of the group ? 1298 05b5cc6e1e4d2b4197774ebca
5b5cc6e1e4d2b4197774ebca- 1708false
- 2392true
- 3618false
- 4816false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "392"
Explanation :
Answer: B) 392 Explanation: The sum of the digits in 708, 618 and 816 is 15, but not in 392.
Q: A drink vendor has 368 liters of Maaza, 80 liters of Pepsi and 144 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required ? 1332 05b5cc6e1e4d2b4197774ebc5
5b5cc6e1e4d2b4197774ebc5- 147false
- 246false
- 337true
- 435false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "37"
Explanation :
Answer: C) 37 Explanation: The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.Number of cans of Maaza = 368/16 = 23Number of cans of Pepsi = 80/16 = 5Number of cans of Sprite = 144/16 = 9The total number of cans required = 23 + 5 + 9 = 37 cans.
Q: Five men and nine women can do a piece of work in 10 days. Six men and twelve women can do the same work in 8 days. In how many days can three men and three women do the work ? 3754 05b5cc6e1e4d2b4197774ebbb
5b5cc6e1e4d2b4197774ebbb- 118 daysfalse
- 220 daystrue
- 316 daysfalse
- 414 daysfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "20 days"
Explanation :
Answer: B) 20 days Explanation: (5m + 9w)10 = (6m + 12w)8 => 50m + 90w = 48w + 96 w => 1m = 3w 5m + 9w = 5m + 3m = 8m 8 men can do the work in 10 days. 3m +3w = 3m + 1w = 4m So, 4 men can do the work in (10 x 8)/4 = 20 days.
Q: A work which could be finished in 11 days was finished 4 days earlier after 4 more men joined. The number of men employed was ? 1394 05b5cc6e1e4d2b4197774ebb6
5b5cc6e1e4d2b4197774ebb6- 17true
- 28false
- 39false
- 410false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "7"
Explanation :
Answer: A) 7 Explanation: As the work is sameM1D1 = M2D2 Here Let the number of men employed was M=> 11M = 7(M+4)=> 11M - 7M = 28=> M = 7
Q: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2490 ? 2577 05b5cc6e1e4d2b4197774ebb1
5b5cc6e1e4d2b4197774ebb1- 1Rs. 820false
- 2Rs. 830true
- 3Rs. 840false
- 4Rs. 850false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "Rs. 830"
Explanation :
Answer: B) Rs. 830 Explanation: Let the total amount in the partnership be 'x'.Then A's share = x/3B's share = x/4C's share = x/5D's share = x - (x/3 + x/4 +x/5) = 13x/60 A : B : C : D = x/3 : x/4 : x/5 : 13x/60 = 20 : 15 : 12 : 13 A's share in the profit of Rs. 2490 = 20 (2490/60) = Rs. 830.
Q: The number of sequences in which 4 players can sing a song, so that the youngest player may not be the last is ? 1202 05b5cc6e1e4d2b4197774ebac
5b5cc6e1e4d2b4197774ebac- 12580false
- 23687false
- 34320true
- 45460false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "4320"
Explanation :
Answer: C) 4320 Explanation: Let 'Y' be the youngest player. The last song can be sung by any of the remaining 3 players. The first 3 players can sing the song in (3!) ways. The required number of ways = 3(3!) = 4320.