Quantitative Aptitude Practice Question and Answer
8Q: One girl can eat 112 chocolates in half a minute, and her boy friend can eat half as many in twice the length of time. How many chocolates can both boy and girl eat in 12 seconds ? 1711 05b5cc745e4d2b4197774fa27
5b5cc745e4d2b4197774fa27- 144false
- 232false
- 356true
- 449false
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Answer : 3. "56"
Explanation :
Answer: C) 56 Explanation: Girl eats 112 chocolates in 30 sec so she can eat in 12 sec is 12 x 112/30 = 44.8 chocolates. Her boy friend can eat one-half of 112 in twice of 30 sec so he can eat 56 in 60 sec Then he can eat in 12 sec is 56 x 12/60 = 11.2 chocolates. Hence, together they can eat = 44.8 + 11.2 =56 chocolates in 12 seconds.
Q: 1397 x 1397 = ? Here what replaces '?' 1706 05b5cc6bbe4d2b4197774d853
5b5cc6bbe4d2b4197774d853- 11951609true
- 21821504false
- 32031489false
- 41847879false
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Answer : 1. "1951609"
Explanation :
Answer: A) 1951609 Explanation: 1397 x 1397
Q: Sixty men can stitch 150 shirts in 30 days working 8 hours a day. In how many days can 35 men stitch 200 shirts working 6 hours a day ? 1706 05b5cc6dce4d2b4197774e9c9
5b5cc6dce4d2b4197774e9c9- 187.5false
- 289false
- 391.5true
- 493.5false
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Answer : 3. "91.5"
Explanation :
Answer: C) 91.5 Explanation: We have M1 D1 H1 / W1 = M2 D2 H2 / W2 (Variation rule)(60 x 30 x 8)/ 150 = (35 x D2 x 6) / 200 D2 = (60 x 30 x 8 x 200) / (150 x 35 x 6) => D2 = 91.42 days =~ 91.5 days.
Q: Find the next number in the number series? 1, 4, 12, 32, ? 1703 05b5cc6a8e4d2b4197774ce61
5b5cc6a8e4d2b4197774ce61- 180true
- 2100false
- 3192false
- 4169false
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Answer : 1. "80"
Explanation :
Answer: A) 80 Explanation: Next number of the sequence 1, 4, 12, 32,... 1 = 2 x 20 4 = 2 x 21 12 = 3 x 22 32 = 4 x 23 80 = 5 x 24.
Q: A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most ? 1703 05b5cc6e1e4d2b4197774ebde
5b5cc6e1e4d2b4197774ebde- 1215true
- 2268false
- 3254false
- 4216false
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Answer : 1. "215"
Explanation :
Answer: A) 215 Explanation: Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 x 6 x 6 = 216. Of these attempts, one of them is a successful attempt. Maximum number of unsuccessful attempts = 216 - 1 = 215.
Q: In a test, minimum passing percentage for girls and boys is 35% and 40% respectively. A boy scored 483 marks and failed by 117 marks. What is the minimum passing marks for girls ? 1703 05b5cc72ce4d2b4197774f75a
5b5cc72ce4d2b4197774f75a- 1625false
- 2525true
- 3425false
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Answer : 2. "525"
Explanation :
Answer: B) 525 Explanation: Given 40% minimum passing marks for boys = 483 + 117 = 600=> 1% = 600/40 => 100% = 600 x 100/40 = 1500Minimum passing marks for girls = 35% of 1500 = 35 x 1500/100 = 525.
Q: A letter is takenout at random from 'ASSISTANT' and another is taken out from 'STATISTICS'. The probability that they are the same letter is : 1701 05b5cc7d0e4d2b41977751213
5b5cc7d0e4d2b41977751213- 135/96false
- 219/90true
- 319/96false
- 4None of thesefalse
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Answer : 2. "19/90"
Explanation :
Answer: B) 19/90 Explanation: ASSISTANT→AAINSSSTT STATISTICS→ACIISSSTTT Here N and C are not common and same letters can be A, I, S, T. Therefore Probability of choosing A = 2C19C1×1C110C1 = 1/45 Probability of choosing I = 19C1×2C110C1 = 1/45 Probability of choosing S = 3C19C1×3C110C1 = 1/10 Probability of choosing T = 2C19C1×3C110C1 = 1/15 Hence, Required probability = 145+145+110+115= 1990
Q: Anil purchases two books for Rs.100. He sells first at loss of 5% and second al 20% profit. If he gets Overall profit of 5% then what is cost of first book? 1699 05b5cc60de4d2b4197774b61d
5b5cc60de4d2b4197774b61d- 158false
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Answer : 2. "60"
Explanation :
Answer: B) 60 Explanation: -5-----------------------5-------------------20 5-(-5) = 10 20-5= 15 Ratio of cost price of book1 and book2 = 3:2 Then cost price of book 1 is given by (3/5) x 100 = Rs. 60.