Answer: C) 32 mts Explanation: let 'b' be the Length of bridge from cow to the near end of the bridge and 'a' be the distance of the train from the bridge. 'x' be speed of cow => '4x' speed of trainThen the total length of the bridge 2b + 10.(a-2)/4x = b/x=> a-2 = 4b........(1)Now if it had run in opposite direction(a+2b+10-2)/4x = (b+10-2)/x=> a - 2b = 24......(2)Solving (1) and (2)b = 11 , Therefore length of the bridge is 2 x 11 + 10 = 32mts.

Answer: B) 9 km/hr, 3 km/hr Explanation: Let the speed of the boat = p kmph Let the speed of the river flow = q kmph From the given data, 2 x 28p + q = 28p - q   => 56p - 56q -28p - 28q = 0 => 28p = 84q => p = 3q. Now, given that if 283q + 2q + 283q - 2q = 67260=> 285q + 28q = 67260=> q = 3 kmph=> x  =3q = 9 kmph   Hence, the speed of the boat = p kmph = 9 kmph and the speed of the river flow = q kmph = 3 kmph.

Answer: A) 1.25 kg Explanation: Let the initial amount of honey in the jar was k, then    512 = k1 - 154 or  512 = k454   => k = 512 × 625256  => k = 1250    Hence initially the honey in the jar = 1.25 kg