Aptitude Practice Question and Answer
8Q: A 200 m long train passes a motorcycler, running in the same direction at 12 km/hr, in 15 second and a jeep travelling in the same direction in 20 s. At what speed is the car travelling (length of both the motorcycler and jeep is negligible)? 2517 05b5cc607e4d2b4197774b502
5b5cc607e4d2b4197774b502- 136 kmphfalse
- 232 kmphfalse
- 329 kmphfalse
- 424 kmphtrue
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Answer : 4. "24 kmph"
Explanation :
Answer: D) 24 kmph Explanation: Let the speed of the train be 'S' kmph From the given data, Distance = Length of train = D = 200 mts = 200 x 18/5 kms Time = 10 sec given speed of the motorcycler = 12 kmph Relative speed as they are moving in the same direction = (S - 12) kmph (S- 12) = 200 x 18515S - 12 = 48S = 60 kmph Hence, the speed of the train = S = 60 kmph Now, Let the speed of the jeep be 'x' kmph 60 - x = 200 x 1852060 - x = 36x = 60 - 36x = 24 kmph Therefore, the speed of the jeep = x = 24 kmph.
Q: Akhil after travelling 50 km meets Raju who suggests him to go slower. He then proceeds at ¾ of his former speed and arrives at his destination 35 minutes late. Had the meeting occurred 24 km further Akhil would have reached its destination 25 minutes late. What is the initial speed of Akhil? 3187 05b5cc601e4d2b4197774b476
5b5cc601e4d2b4197774b476- 148 kmphtrue
- 236 kmphfalse
- 324 kmphfalse
- 420 kmphfalse
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Answer : 1. "48 kmph"
Explanation :
Answer: A) 48 kmph Explanation: Let the initial speed of Akhil be '4p' kmph Then speed after decrease in speed = '3p' kmph We know that, Change in speed == Change in time According to the given data, 243p - 244p = 35 - 2560=> p = 12 Hence, the initial speed of Akhil = 4p = 4 x 12 = 48 kmph.
Q: In a class 60% of the students pass in English and 45% pass in Hindi. If 25% of them pass in both subjects, what percentage of the students fail in both the subjects? 2678 15b5cc601e4d2b4197774b440
5b5cc601e4d2b4197774b440- 120%true
- 225%false
- 330%false
- 415%false
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Answer : 1. "20%"
Explanation :
Answer: A) 20% Explanation: Percentage of students passed in English = 60% Percentage of students passed in Hindi = 45% Percentage of students passed in both subjects = 25% ATQ, Percentage of students passed in only English = 60 - 25 = 35% Percentage of students passed in only Hindi = 45 - 25 = 20% Therefore, Percentage of students failed = 100 - (35 + 25 + 20) = 100 - 80 = 20%.
Q: How many window coverings are necessary to span 50 windows, if each window covering is 15 windows long? 2944 05b5cc601e4d2b4197774b453
5b5cc601e4d2b4197774b453- 14true
- 215false
- 33false
- 450false
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Answer : 1. "4"
Explanation :
Answer: A) 4 Explanation: Given that, Number of windows = 50 Each window covering covers 15 windows => 50 windows requires 50/15 window coverings = 50/15 = 3.333 Hence, more than 3 window coverings are required. In the options 4 is more than 3. Hence, 4 window coverings are required to cover 50 windows of each covering covers 15 windows.
Q: Compounding interest means interest accrues 1565 15b5cc604e4d2b4197774b4b8
5b5cc604e4d2b4197774b4b8- 1at variable rates throughout the termfalse
- 2more quickly than simple interesttrue
- 3more slowly than simple interestfalse
- 4at the same rate as simple interestfalse
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Answer : 2. "more quickly than simple interest"
Explanation :
Answer: B) more quickly than simple interest Explanation: Compounding interest means interest accrues on the interest charged and the principal amount each period the interest is charged. Compound interest is calculated by multiplying the principal amount by one plus the annual interest rate raised to the number of compound periods minus one.The total initial amount of the loan is then subtracted from the resulting value. The formula for calculating compound interest is: [P (1 + i)n] – P = P [(1 + i)n – 1] (Where P = Principal, i = nominal annual interest rate in percentage terms, and n = number of compounding periods.) Take a three-year loan of Rs. 10,000 at an interest rate of 5% that compounds annually. What would be the amount of interest? In this case, it would be: Rs. 10,000 [(1 + 0.05)3] – 1 = 10,000 [1.157625 – 1] = Rs. 1,576.25. How it grows ::
Q: The difference between 4632 and 20000 is what number 2888 05b5cc5ffe4d2b4197774b42c
5b5cc5ffe4d2b4197774b42c- 115368true
- 212652false
- 314562false
- 414965false
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Answer : 1. "15368"
Explanation :
Answer: A) 15368 Explanation: The difference between 4632 and 20000 is given by subtracting smaler number from the bigger number. Here the bigger number is 20000 Smaller number is 4632 Now, subtracting 4632 from 20000 20000 - 4632 = 15368 and the resut is an even number. Hence, The difference between 4632 and 20000 is 15368 and is an even number.
Q: The ages of Sunitha and Pranitha are 40 years and 60 years, respectively. How many years before the ratio of their ages was 3 : 5? 1490 05b5cc601e4d2b4197774b445
5b5cc601e4d2b4197774b445- 110 yearstrue
- 215 yearsfalse
- 318 yearsfalse
- 424 yearsfalse
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Answer : 1. "10 years"
Explanation :
Answer: A) 10 years Explanation: Given the ages of Sunitha and Pranitha are 40 years and 60 years. Let before 'm' years, their ages be in the ratio of 3 : 5 ATQ, 40-m60-m = 35 => 200 - 5m = 180 - 3m =>2m = 20 => m = 10 years.
Q: Which of the following fraction is the largest? 1235 15b5cc604e4d2b4197774b4da
5b5cc604e4d2b4197774b4da- 17/12true
- 29/16false
- 313/20false
- 432/80false
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Answer : 1. "7/12"
Explanation :
Answer: A) 7/12 Explanation: Here to say which fraction is greater from the given options, the fraction with greater numerator with same denominator or smaller denominator with same numerator. To find the greater fraction, among the given options, make the denominators same for the options by finding the LCM of all the denominators. 7/12, 9/16, 13/20, 32/80 Now, LCM of 12, 16, 20, 80 = 240. Then, 140/240, 135/240, 156/240, 96/240 Here 156240 > 140240 > 135240 > 96240=> 1320 > 712 > 916 > 3280 Hence, largest fraction = 13/20.