II. y2 + 16y + 63 = 0
2429 05eb1553b5a48d373519c9cf25eb1553b5a48d373519c9cf2In the following questions two equations numbered I and II are given. You have to solve both the equations and ____
(A) x>y
(B) x≥y
(C) x<y
(D) x≤y
(E) x=y or the relationship cannot be established
I.\(20x^2 - x - 12 = 0\)
II.\(20y^2 + 27y + 9 = 0\)
In the following questions two equations numbered I and II are given. You have to solve both the equations and ____
I.$$ {7\over \sqrt {x}}+{5\over \sqrt {x}}=\sqrt {x}$$
II.$${y^2 - {12^{5/2}\over \sqrt {y}}}= 0$$
Give answer
(A) x > y
(B) x ≥ y
(C) x < y
(D) x ≤ y
(E) x=y or the relationship cannot be established
Direction: In the following questions two equations numbered I and II are given. You have to solve both the equations and Give answer
Give answer (A) If x > y
Give answer (B) if x ≥ y
Give answer (C) if x<y
Give answer (D) If x ≤ y
Give answer (E) if x=y or the relationship cannot be established.
I. x2 – 7x+ 12=0
II. y2-12y+32 =0
Find the exact value of the following question:
$$ 1280÷{2^3} + 1220÷{2^2}-182=?$$
1037 05e93e9e53d193e3bf6fdf226If 3x+0.04x=0.608, find x.
1322 05ebceaa8d33dc17bd4957b88