Directions: In the following question, two equations are given in variables X and Y. You have to solve these equations and determine the relation between X and Y.

I. X² – 5x + 6 = 0
 II. Y² – y – 6 = 0

A root of equation $$({ax}^2+bx+c)$$ (where a, b and c are rational numbers) is 5 +3√3. What is the value of $$({a}^2+b^2+c^2) / (a+b+c) ? $$

Direction: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.
(A) x>y
(B) x≥y
(C) x˂y
(D) x≤y
(E) x=y or the relations ship cannot be established

I.x³-371 = 629
II.y³ - 543 = 788 

In the following questions two equations numbered I and II are given. You have to solve both the equations and ____
(A) x>y
(B) x≥y
(C) x<y
(D) x≤y
(E) x=y or the relationship cannot be established
I.\(20x^2 - x - 12 = 0\)
II.\(20y^2 + 27y + 9 = 0\)

In the following questions two equations numbered I and II are given. You have to solve both the equations and ____
I.$$ {7\over \sqrt {x}}+{5\over \sqrt {x}}=\sqrt {x}$$
II.$${y^2 - {12^{5/2}\over \sqrt {y}}}= 0$$
Give answer
(A) x > y
(B) x ≥ y
(C) x < y
(D) x ≤ y
(E) x=y or the relationship cannot be established

Direction: In the following questions two equations numbered I and II are given. You have to solve both the equations and Give answer

Give answer (A) If x > y
Give answer (B) if x ≥ y
Give answer (C) if x<y
Give answer (D) If x ≤ y
Give answer (E) if x=y or the relationship cannot be established.

 I. x² – 7x+ 12=0
II. y²-12y+32 =0

Find the exact value of the following question:

$$ 1280÷{2^3} + 1220÷{2^2}-182=?$$

If 3x+0.04x=0.608, find x.