GATE Practice Question and Answer
8Q: Ram and Raj start a business with investments of Rs. 2500 and Rs. 2250 respectively. After 2 months, Ram takes out Rs.1250 from his capital. After 1 more month, Raj takes out Rs.750 of his capital while Rakesh joins them with a capital of Rs. 3500. At the end of 6 months, they earn a profit of Rs. 2540. Which of the following is the share of each member in the profit ? 3073 05b5cc72ce4d2b4197774f783
5b5cc72ce4d2b4197774f783- 1Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840true
- 2Ram - Rs. 900, Raj - Rs. 800, Rakesh - Rs. 840false
- 3Ram - Rs. 840, Raj - Rs. 920, Rakesh - Rs. 840false
- 4Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 940false
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Answer : 1. "Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840"
Explanation :
Answer: A) Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840 Explanation: Initial investment of Ram = Rs.2500.After 2 months he withdraw Rs.1250 from his capital.Therefore, we have, Ram invested Rs.2500 for 2 months and Rs.(2500-1250=) 1250 for 4 months. Raj invested Rs. 2250 for 3 months and Rs.(2250-750=) 1500 for 3 months. And, Rakesh invested Rs.3500 for 3 months; Their investing ratio:Ram:Raj:Rakesh = (2500x2 + 1250x4):(2250x3 + 1500x3):(3500x3)= (10,000):(11,250):(10,500) = 1000:1125:1050 = 40:45:42 Total profit for 6 months = Rs.2540Therefore, Ram's share = Rs.(2540 x 40/(40+45+42)) = Rs.(2540 x 40/127) = Rs.800Raj's share = Rs.(2540 x 45/127) = Rs.900Rakesh's share = Rs.(2540 x 42/127) = Rs.840
Q: In these series, you will be looking at both the letter pattern and the number pattern. Fill the blank in the middle of the series or end of the series.SCD, TEF, UGH, ____, WKL 3070 05b5cc720e4d2b4197774f609
5b5cc720e4d2b4197774f609- 1UJIfalse
- 2VIJtrue
- 3XLMfalse
- 4DOPfalse
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Answer : 2. "VIJ"
Explanation :
Answer: B) VIJ Explanation: First letter series S,T,U,Vsecond and third letter series CD,EF,GH,IJ...so answer = VIJ
Q: If 34 men completed 2/5th of a work in 8 days working 9 hours a day. How many more man should be engaged to finish the rest of the work in 6 days working 9 hours a day ? 3053 05b5cc6d9e4d2b4197774e807
5b5cc6d9e4d2b4197774e807- 1101 menfalse
- 2112 menfalse
- 3102 mentrue
- 4120 menfalse
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Answer : 3. "102 men"
Explanation :
Answer: C) 102 men Explanation: From the above formula i.e (m1 x t1/w1) = (m2 x t2/w2) so, [(34 x 8 x 9)/(2/5)] = [(M x 6 x 9)/(3/5)] so, M = 136 men Number of men to be added to finish the work = 136-34 = 102 men.
Q: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ? 3050 05b5cc6dce4d2b4197774e960
5b5cc6dce4d2b4197774e960- 15:3false
- 21:4false
- 34:1false
- 49:1true
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Answer : 4. "9:1"
Explanation :
Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters. Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters 10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters. The ratio of milk and water in the new mixture = 16:4 = 4:1 If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters. Amount of water removed = 2 liters. Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters. Now 10 lts milk is added => total milk = 18 lts The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
Q: If 10 men take 15 days to complete a work. In how many days will 37 men complete the work? 3045 05b5cc6bfe4d2b4197774da3d
5b5cc6bfe4d2b4197774da3d- 13 daysfalse
- 24 daystrue
- 35 daysfalse
- 46 daysfalse
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Answer : 2. "4 days"
Explanation :
Answer: B) 4 days Explanation: Given 10 men take 15 days to complete a work => Total mandays = 15 x 10 = 150 Let the work be 150 mandays. => Now 37 men can do 150 mandays in 150/37 =~ 4 days
Q: Study of sound is called 3042 05b5cc6aae4d2b4197774cf38
5b5cc6aae4d2b4197774cf38- 1Agronomyfalse
- 2Accousticstrue
- 3Aestheticsfalse
- 4Aeronauticsfalse
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Answer : 2. "Accoustics"
Explanation :
Answer: B) Accoustics Explanation: Accoustics is a subject deals with the Study of sound Aesthetics is a Philosophy of fine arts The science or art of flight is called Aeronautics The science of soil management is called Agronomy.
Q: A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement ? 3016 05b5cc6e7e4d2b4197774edb0
5b5cc6e7e4d2b4197774edb0- 11900true
- 22100false
- 31700false
- 42000false
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Answer : 1. "1900"
Explanation :
Answer: A) 1900 Explanation: Given 2000 ---- 54 days The provisions for 2000 men for 39 days can be completed by 'm' men for only 20 days. i.e, 2000 ----- 39 days == m ---- 20 days => m x 20 = 2000 x 39 m = 3900 So total men for 20 days is 3900 => 2000 old and 1900 new reinforcement. Hence, reinforcement = 1900.
Q: Find the odd one out of the floowing number series? 270, 261, 279, 252, 289, 243 3015 05b5cc639e4d2b4197774ba8c
5b5cc639e4d2b4197774ba8c- 1270false
- 2279false
- 3289true
- 4243false
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Answer : 3. "289"
Explanation :
Answer: C) 289 Explanation: Here the given number series is 270, 261, 279, 252, 289, 243 270 - 9 = 261 261 + 18 = 279 279 - 27 = 252 252 + 36 = 288 (not equals to 289) 288 - 45 = 243 Hence, the odd number in the given number series is 289.

