Quantitative Aptitude Practice Question and Answer
8Q: Rs. 2600 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/2:1/3:1/4 ? 2817 05b5cc6d8e4d2b4197774e7bf
5b5cc6d8e4d2b4197774e7bf- 1600true
- 2300false
- 3150false
- 475false
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Answer : 1. "600"
Explanation :
Answer: A) 600 Explanation: 1/2:1/3:1/4 = 6:4:3 As the difference is 3 => 3/13x2600 = 600
Q: Ratio of the ages of Mahesh and Nilesh is 5 : x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x ? 2814 05b5cc6dce4d2b4197774e9bf
5b5cc6dce4d2b4197774e9bf- 111.8false
- 212.9false
- 313.7false
- 414.5true
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Answer : 4. "14.5"
Explanation :
Answer: D) 14.5 Explanation: Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.k/l = 5/x ------ (1)k = m - 18 ------ (2)m + 9 = 47 ------ (3)k - l = m ----- (4)(3) => m = 47 - 9 = 38 years(2) => k = 38 -18 = 20 years(1) => 20/l = 5/x => l = 4x(4) => 4x - 20 = 38=> 4x = 58 => x = 14.5
Q: Ram can complete ¼ th part of work in 8 days and Shyam can complete 2/4 th of the work in 6 days and Naresh can complete ¾th the work in 12 days. In how many days can they together complete it? 2811 15d147f2b9aeb0a08f1e6721a
5d147f2b9aeb0a08f1e6721a- 1false
- 2true
- 3false
- 4false
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Answer : 2. " "
Q: Sum of the ages of Rajesh, Suresh, Mahesh and Dinesh is 76 years. 7 years hence, their age ratio is 7:6:5:8. Find Mahesh’s present age ? 2808 05b5cc6c2e4d2b4197774dba5
5b5cc6c2e4d2b4197774dba5- 117 yearsfalse
- 213 yearstrue
- 314 yearsfalse
- 416 yearsfalse
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Answer : 2. "13 years"
Explanation :
Answer: B) 13 years Explanation: Given R + S + M + D = 76 => R+7 : S+7 : M+7 : D+7 = 7:6:5:8 => Let the ratio = x => M+7 = 5x => M = 5x-7 => R = 7x-7 => S = 6x-7 => D = 8x-7 => R + S + M + D = 76 => 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76 => 26x - 28 = 76 => 26x = 104 => x = 4 => Mahesh's present age = 5x-7 = 20 - 7 = 13 years.
Q: Find the odd one out of the following number series? 9 5 6 14 56 488 2807 05b5cc66de4d2b4197774bfb0
5b5cc66de4d2b4197774bfb0- 156true
- 26false
- 314false
- 45false
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Answer : 1. "56"
Explanation :
Answer: A) 56 Explanation: The given number series follows a pattern that, 9 9 x 0.5 + 0.5 = 5 5 x 1 + 1 = 6 6 x 2 + 2 = 14 14 x 4 + 4 = 60 (not equals to 56) 60 x 8 + 8 = 488. Hence, the odd one in the given number series is 56.
Q: A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ? 2802 05b5cc720e4d2b4197774f613
5b5cc720e4d2b4197774f613- 145false
- 224false
- 342false
- 454true
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Answer : 4. "54"
Explanation :
Answer: D) 54 Explanation: By trial and error method from the given options, as 54 - 45 = (1/11) x (45+54) = 99/11 = 9 Hence this satisfies the given conditions. Then the woman's husband age is 54.
Q: A is thrice as fast as B. Together they can do a job in 15 days. In how many days will B finish the work? 2787 05d1488909aeb0a08f1e67455
5d1488909aeb0a08f1e67455- 140false
- 260true
- 330false
- 420false
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Answer : 2. "60"
Q: The number of permutations of the letters of the word 'MESMERISE' is ? 2785 05b5cc6ebe4d2b4197774ee5f
5b5cc6ebe4d2b4197774ee5f- 19!/(2!)^{2}x3!true
- 29! x 2! x 3!false
- 30false
- 4Nonefalse
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Answer : 1. "9!/(2!)^{2}x3!"
Explanation :
Answer: A) 9!/(2!)^{2}x3! Explanation: n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.The letter pattern 'MESMERISE' consists of 10 letters of which there are 2M's, 3E's, 2S's and 1I and 1R.Number of arrangements = 9!(2!)2×3!