Quantitative Aptitude Practice Question and Answer

Q: A rectangular block has the dimensions 5x6x7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm. If the level of the fluid in the cylinder rises by 4 cm, What portion of the block is immersed in the fluid ? 2597 0

  • 1
    22/7 x 24/35
    Correct
    Wrong
  • 2
    22/7 x 36 x 4
    Correct
    Wrong
  • 3
    22/7 x 36/5
    Correct
    Wrong
  • 4
    22/7 x 37/21
    Correct
    Wrong
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Answer : 1. "22/7 x 24/35"
Explanation :

Answer: A) 22/7 x 24/35 Explanation: Since level of water increased in cylinder by height 4.  This is because of the rectangular block .   Therefore , area of rectangular block immersed in water is  = 227×6×6×4   Thats why portion of block immersed in water is  = (22/7 * 36 * 4) / total vol. of rectangle  = (22/7 * 36 * 4)/ (7*5*6)  = (22/7 * 24)/ 35.

Q: A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group ? 2597 0

  • 1
    600
    Correct
    Wrong
  • 2
    610
    Correct
    Wrong
  • 3
    609
    Correct
    Wrong
  • 4
    599
    Correct
    Wrong
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Answer : 1. "600"
Explanation :

Answer: A) 600 Explanation: Two men, three women and one child can be selected in ⁴C₂ x ⁶C₃ x ⁵C₁ ways = 600 ways.

Q: The average age of a couple and their son was 40 years, the son got married and a child was born just two years after their marriage. When child turned to 10 years, then the average age of the family becomes 38 years. What was the age of the daughter in law at the time of marriage ? 2596 0

  • 1
    12 years
    Correct
    Wrong
  • 2
    10 years
    Correct
    Wrong
  • 3
    14 years
    Correct
    Wrong
  • 4
    13 years
    Correct
    Wrong
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Answer : 1. "12 years"
Explanation :

Answer: A) 12 years Explanation: Given the average age of couple and their son = 40 => Sum of age (H +W +S) = 40×3 Let the age of daughter in law at the time of marriage = D years Now after 10 years, (H + S +W) + 3×12 + D +12 + 10 = 38×5 178 + D = 190 D = 190 -178 = 12 years

Q: Ram can complete ¼ th part of work in 8 days and Shyam can complete 2/4 th of the work in 6 days and Naresh can complete ¾th the work in 12 days. In how many days can they together complete it? 2588 1

  • 1
    \(6 {11 \over 17 }\)
    Correct
    Wrong
  • 2
    \(5 {11 \over 17 }\)
    Correct
    Wrong
  • 3
    \(8 {11 \over 17 }\)
    Correct
    Wrong
  • 4
    \(7 {11 \over 17 }\)
    Correct
    Wrong
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Answer : 2. "\(5 {11 \over 17 }\)"

Q: K can build a wall in 30 days. L can demolish that wall in 60 days. If K and L work on alternate days, when will the wall be completed ? 2583 1

  • 1
    120 days
    Correct
    Wrong
  • 2
    119 days
    Correct
    Wrong
  • 3
    118 days
    Correct
    Wrong
  • 4
    117 days
    Correct
    Wrong
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Answer : 4. "117 days"
Explanation :

Answer: D) 117 days Explanation: K's work in a day(1st day) = 1/30L's work in a day(2nd day)= -1/60(demolishing)hence in 2 days, combined work= 1/30 - 1/60 =1/60since both works alternatively, K will work in odd days and L will work in even days.1/60 unit work is done in 2 days58/60 unit work will be done in 2 x 58 days = 116 daysRemaining work = 1-58/60 = 1/30Next day, it will be K's turn and K will finish the remaining 1/30 work.hence total days = 116 + 1 = 117.

Q: A merchant buys two items for Rs. 7500. One item he sells at a profit of 16% and the other item at 14% loss. In the deal, the merchant makes neither any profit nor any loss. What is the difference between the selling price of both the items? 2581 0

  • 1
    Rs. 620
    Correct
    Wrong
  • 2
    Rs. 654
    Correct
    Wrong
  • 3
    Rs. 725
    Correct
    Wrong
  • 4
    Rs. 747
    Correct
    Wrong
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Answer : 1. "Rs. 620"
Explanation :

Answer: A) Rs. 620 Explanation: Let the C.P of one item is Rs. P and that of other is Rs. (7500 - P) According to the data given C.P = S.P => Px(116/100) + (7500-P)x(86/100) = 7500 => 30P = 105000 => P = 3500 Required difference between selling prices = Rs. [(3500/100) x 116] - [(4000/100) x 86] = 4060-3440 = Rs. 620

Q: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2490 ? 2577 0

  • 1
    Rs. 820
    Correct
    Wrong
  • 2
    Rs. 830
    Correct
    Wrong
  • 3
    Rs. 840
    Correct
    Wrong
  • 4
    Rs. 850
    Correct
    Wrong
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Answer : 2. "Rs. 830"
Explanation :

Answer: B) Rs. 830 Explanation: Let the total amount in the partnership be 'x'.Then A's share = x/3B's share = x/4C's share = x/5D's share = x - (x/3 + x/4 +x/5) = 13x/60 A : B : C : D = x/3 : x/4 : x/5 : 13x/60 = 20 : 15 : 12 : 13 A's share in the profit of Rs. 2490 = 20 (2490/60) = Rs. 830.

Q: The average age of seven persons sitting in a row facing east is 26 years. If the average age of the first three persons is 19 years and the average age of the last three persons is 32 years, then find the age of the person sitting in the middle of the row ? 2568 0

  • 1
    32 yrs
    Correct
    Wrong
  • 2
    29 yrs
    Correct
    Wrong
  • 3
    24 yrs
    Correct
    Wrong
  • 4
    27 yrs
    Correct
    Wrong
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Answer : 2. "29 yrs"
Explanation :

Answer: B) 29 yrs Explanation: Total age seven persons = (26 x 7)yearsTotal age of the first three persons and the last three persons are (19 x 3) years and (32 x 3) years respectively.Age of the person sitting in the middle of the row = 26 x 7 - 19 x 3 - 32 x 3 = 182 - 57 - 96 = 29 years.

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